3 the radius of both bases are the sams
Answer:
The answer to your question is letter B
Step-by-step explanation:
Process
1.- Write the equation
f(x) = 2x + 1
find f(2)
2.- Substitute x for 2
f(2) = 2(2) + 1
3.- Simplify
f(2) = 4 + 1
f(2) = 5
Answer:
A) (1 s, 2.3 s)
B) (-4 m/s², 3.8 m/s²)
Step-by-step explanation:
The car's position which is the distance is given by the equation;
s(t) = t³ - 5t² + 7t
A) Velocity is the first derivative of the distance. Thus;
v(t) = ds/dt = 3t² - 10t + 7
At v = 0, we have;
3t² - 10t + 7 = 0
Using quadratic formula, we have;
t = 1 and t = 2.3
Thus, time at velocity of 0 is t = (1 s, 2.3 s)
B) acceleration is the derivative of the velocity. Thus;
a(t) = dV/dt = 6t - 10
At velocity of 0, we got t = 1 and t = 2.3
Thus;
a(1) = 6(1) - 10 = -4 m/s²
a(2.3) = 6(2.3) - 10 = 3.8 m/s
Thus, a(t) at v = 0 gives; (-4 m/s², 3.8 m/s²)
There are 90 ways where you can wear one bracelet and one necklace.
Answer:
Step-by-step explanation:
y-(-2) = 1/2(x-12)
y+2 = 1/2x - 6
y = 1/2x -8
y = mx +b
