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zlopas [31]
3 years ago
15

W (5x- 12) z Y (2x - 3)° X = m

Mathematics
1 answer:
german3 years ago
8 0

Answer:

<VYX +<YVX+<VXY=180 SUM OF THE INTERIOR ANGLE OF THE TRIANGLE

90+5X-12+2X-3=180

7X=180-75

X=105/7=15

X=15°

again

in right angled triangle XYZ

<Y+<Z+<X=180

<y+90+2×15-3=180

[here diagonal of the rectangular bisect each at 90°]

<Y=180-117=63°

M<VWZ= <XYZ=63° alternate angle

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How do you do 3(4y-7)=15y+6​
cestrela7 [59]

Answer:

y = 27/7

Step-by-step explanation:

Perform the indicated multiplication:

3(4y-7)=15y+6 becomes:

12y - 21 = 5y + 6

Combining like terms, we get:

7y = 27, so that y = 27/7

7 0
4 years ago
The first three steps in determining the solution set of the system of equations algebraically are shown in the table. y = −x2 +
lianna [129]
You have a system of equations \left \{ {{y = -x^2+2x-9} \atop {y =-6x+6}} \right..

1. Substitude right side of second equation into the left side of the first equation: -6x+6=-x^2+2x-9.

2. Solve this equation:
 x^2-2x+9-6x+6=0, \\ x^2-8x+15=0, \\ D=(-8)^2-4\cdot 1\cdot 15=64-60=4,  \\ \sqrt{D}=2,  \\ x_{1,2}=\dfrac{8\pm 2}{2  } =3,5.

3. Find y:
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7 0
4 years ago
Read 2 more answers
Simplify square root of 24 times square root of 2x times square root of 3x
sveticcg [70]
\sqrt{24} * \sqrt{2x} * \sqrt{3x} =  \sqrt{2*2*2*3}* \sqrt{2*x} * \sqrt{3*x} =  \sqrt{2*2*2*2*3*3*x*x} = 2*2*3*x = 12x
3 0
4 years ago
Name
Rudiy27

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3 0
3 years ago
For concreatting a tower cement, sand, stones are in the ratio 1:2:4 For 144kg sand.. What amount of cement is required?
Verdich [7]

Answer:

72 kg

Step-by-step explanation:

For concreatting a tower cement, sand, stones are in the ratio 1:2:4 For 144kg sand.. What amount of cement is required?

We are given the ratio

cement: sand:stones

= 1:2:4

The sum of proportion =

1 + 2 + 4 = 7

We are given the kg of sand = 144kg

Step 1

We find the total kg of cement, sand and stones = x

Using the proportion of sand,

2/7 of x = 144kg

2/7 × x = 144kg

2x/7 = 144kg

Cross Multiply

2x = 7 × 144kg

x = 7 × 144kg/2

x = 504kg

Therefore the total kg of cement, sand and stone = 504kg

Step 2

The amount of cement required is calculated as:

1/7 × 504 kg = 72 kg

Therefore, 72kg of cement is required.

4 0
3 years ago
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