This polynomial does not factor so you have to complete the square or use Quadratic formula.
x^2 + 6x + 7 = 0
Using completing the square, subtract 7 from both sides.
x^2 + 6x = -7
divide 6 by 2 = 3, square 3 = 9, add 9 to both sides.
x^2 + 6x + 9 = 2
(x + 3)^2 = 2
Take the sqrt of both sides
x + 3 = + - sqrt 2
subtract 3 from both sides
x = - 3 + - sqrt 2
This is not an answer choice but it is the correct answer. You either typed the choices incorrectly or the equation incorrectly.
Taking the square root of both sides gives two possible cases,
or
Recall that
If 
and 
, we have
so in the equations above, we can write
Then in the first case,
(where 
is any integer)
and in the second,
Then the solutions that fall in the interval 
are
Try this solution, note, checking was not performed.
1) y=(7/2)x-2.
Slope is the coefficient of x, that is 7/2
Intercept x is the value of x when y = 0 ==> 0=(7/2) X - 2==> 7/2x=2 &x=4/7
so intercept x, (4/7,0)
Intercept y is the value of y when x=0 ==> y= (7/2).(0) - 2 ==> y = 2
and so intercept y, (0,-2)
Now you will follow the same logic to find the are same questions
2) y= -6x + 3 ==>Slope= -6, Intercept x =1/2 & intercept y=3
3) y=-5 has a slope 0 (it doesn't exist). The graph is a line // to x-axis at y=-5
4)y=(6/5)x + 1:==>Slope= -5/6, Intercept x =-5/6 & intercept y=1
5) y=(1/4)x + 2 ==>Slope= 1/4, Intercept x =-8 & intercept y=2
6) x=5, this ligne is // to y axis at x=-5
We are given with two equations bearing a square root sign within. In this case, the goal of f(x) is to have a value of x not greater than 1 and not less than -1. g(x) should have x only equal to positive numbers. Hence the domain for (f+g) is equal to the positive numbers greater than or equal to 1.in 2. we multiply both functions to give sqrt of x*(1-x2). the domain should be also positive numbers greater than or equal to 1.
