Question

Natalie kicked a soccer ball. The equation h=-16t^2+50t describes the height of the ball (T) seconds after it was kicked. Approximately how many seconds went by before the ball hit the ground?

Answer 1

Answer:

Time, t = 3.125 s

Step-by-step explanation:

The height attained by the ball after it was kicked is given by as a function of time t as :

$h=-16t^2+50t$

It is required to find the time until which the ball hits the ground. At that point, h(t) = 0

So,

$-16t^2+50t=0\\\\t(-16t+50)=0\\\\t=0, -16t+50=0\\\\t=0, 3.125\ s$

So, 3.125 seconds before the ball hit the ground.