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Crank
3 years ago
7

Natalie kicked a soccer ball. The equation h=-16t^2+50t describes the height of the ball (T) seconds after it was kicked. Approx

imately how many seconds went by before the ball hit the ground?
Mathematics
1 answer:
rosijanka [135]3 years ago
4 0

Answer:

Time, t = 3.125 s

Step-by-step explanation:

The height attained by the ball after it was kicked is given by as a function of time t as :

h=-16t^2+50t

It is required to find the time until which the ball hits the ground. At that point, h(t) = 0

So,

-16t^2+50t=0\\\\t(-16t+50)=0\\\\t=0, -16t+50=0\\\\t=0, 3.125\ s

So, 3.125 seconds before the ball hit the ground.

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