The best and most correct answer among the choices provided by the question is the third choice .
In constructing a parallel line, "<span>Without changing the width of the compass, place the compass at S or P and draw an arc similar to the one drawn."</span>
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s = hours it takes the small pipe on its own.
L = hours it takes the large pipe on its own.
we know the small pipe can do it in 11 hours total, so s = 11, so, how much of the whole job has the small done in 1 hour only?
well, if it takes 11 hours to do the whole thing, in 1 hour it has done only 1/11 of the whole job.
we know both pipes working together can do it in 6 hours flat. So in 1 hour only, both of them have done only 1/6 of the whole thing.
in that 1 hour, how much has the large one done? well, it has only done 1/L of the job.
and you can round that up as needed.
Answer:
y = 2
x = 5
Step-by-step explanation:
4x + 5y = 10 | ×3 |
3x - 3y = 21 | ×4 |
12x + 15y = 30
12x - 12y = 84
____________--
27y = -54
y = -54/27
y = 2
4x + 5y = 10 | ×3 |
3x - 3y = 21 | ×5 |
12x + 15y = 30
15x - 15y = 105
____________+
27x = 135
x = 135/27
x = 5
Step-by-step explanation: