Factor out the greatest common factor of each group
a(b+2)+3( b+2)
Factor the polynomial by factoring out the greatest common factor, b+2
(b+2)(a+3)
A(n)=ar^(n-1) so
100=4r^9
25=r^9
ln25=9lnr
ln25/9=lnr
r=e^(ln25/9)
a(n)=4e^((n-1)(ln25/9) if you wanted an approximation...
a(n)=4(1.43^(n-1))
The quadratic formula is ![\frac{-b+-\sqrt[2]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=%5Cfrac%7B-b%2B-%5Csqrt%5B2%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
and in the equation ax^2+bx+c=0
so now all you have to do is substitute the numbers into the quadratic formula
7539 + 3200 = 10739
the answer is 10,739
1/6 bc they all have an equal chance to be all the numbers on the die and their is only 6 numbers on the die so you have 1:6 probability of it being 3