the correct question is
The length of a rectangle is represented by 4a + 3b, and its width is represented by 3a-2b. Write a polynomial for the perimeter of the rectangle. What is the minimum perimeter of the rectangle if a=12 and b is a non-zero whole number?

we know that
Perimeter of a rectangle=2*[length + width]
length=(4a+3b)
width=3a-2b
so
P=2*[(4a+3b)+(3a-2b)]-----> P=2*[7a+b]-----> P=14a+2b

the answer part a) is
A polynomial for the perimeter of the rectangle is P=14a+2b

Part b)
for a=12
P=14*12+2b---------> P=168+2b
the minimum perimeter of the rectangle is for b=1
so
P=168+2*1-----> P=170 units

the answer part b) is
the minimum perimeter of the rectangle is 170 units

6 0

3 years ago

Simplify.

irina1246 [14]

We have,
(2y)^3 × y^-1

Simplify the term (2y)^3

= 8y^3 × y^-1

Now, multiply the terms with the same base y by adding their exponents.

Note: Using exponent product rule x^y × x^z = x^(y+z)

= 8y^{3+(-1)}
= 8y^(3-1)
= 8y^(3-1)
= 8y^2

3 0

3 years ago