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blagie [28]
2 years ago
6

Ray feeds his dog 0.12 kilogram of dry dog food each day. How many kilograms of dry dog food does Ray need to feed his dog for t

he month of March? (March has 31 days.)​
Mathematics
2 answers:
CaHeK987 [17]2 years ago
8 0

Answer:

amount of food feed each day is 0.12 kg

amount of food required to feed in March( 31 days) is 0.12*31

the answer is 3.72kg

kiruha [24]2 years ago
3 0
0.21x31
=6.51kg
Ray need to feed his dog 6.51kg for the month of March.
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Who had this before if so can I get help
telo118 [61]

2*3+4=10

5+2x2=9

4-3+2=3

4*3+2=14

20-4x3+6=14

16-30/2+11=12

24/6*5=20

15/5+2=5

2+2*9-5=15

12-3+4*2=1

12/3+3*4=16

9-6/3=7

16-3*4=4

36/4/9=1

The last one is yours

6 0
2 years ago
The governor is making a visit to your school and you need to assign seating for 14 students. unfortunately there are only six s
Serjik [45]
First seat: 14 candidates to seat
Second seat: 13 candidates to seat
Third seat : 12 candidates
4th seat: 11 candidates
5th seat: 10 candidates
6th seat: 9 candidates

Number of different variations: 14*13*12*11*10*9 = 2,162,160 different ways,


Observe that is 14P6 = 14! / (14-6)! = 14! / 8! = 14*13*12*11*10*9*8! / 8! =

= 14*13*12*11*10*9 

Answer: 2,162,160
4 0
2 years ago
Describe how to use a tens fact to find the difference for 15-8
shusha [124]
You can round 15 to 20, and 8 to 10
7 0
2 years ago
A flower box is 3 ft. Long, 2 3/4 ft. Wide, and 1/2 ft. Deep. How many cubic feet of dirt can it hold? A. 4 1/8 B. 5 3/4 C. 6 1/
pochemuha

Answer:

The box can hold 4 1/8 cubic feet of dirt

Step-by-step explanation:

What we simply have to find here is the volume of dirt it can take

To get this, we have to multiply the dimensions of the box

We have this as follows

Volume or box = length * width * height

Volume of box = 2 3/4 * 1/2 * 3

Volume of box = 11/4 * 3 * 1/2 = 33/8 = 4 1/8 cubic feet

5 0
3 years ago
The height of a rocket launched upward from a 160 foot cliff is modeled by the function h(t)= -16t^2+48t+160, where h is height
aliina [53]

Answer:

5 seconds

Step-by-step explanation:

In order to find the time when it landed, we will have to find the x-intercepts.

Equation given to us : -16t² + 48t + 160

Let's take the GCD, which is -16.

-16( t² - 3t - 10 )

Factoring what's inside the brackets, we get the x-intercepts.

What multiples to -10 but adds up to -3? The numbers are -5 and 2

-16 ( t - 5 ) ( t - 2 )

X-intercepts are t - 5 and t - 2

Which is 5 and 2 seconds. But one of this is an extraneous solution and that is 2.

If we substitute the value of 2 in the equation, we will not get 0.

During the x-intercept, the x has a value and y is 0. If we substitute 5 ans x. we will get y as 0.

Hence, the answer is 5 seconds.

6 0
3 years ago
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