<span>21.50 + t = 23.22
t = 23.22 - 21.50
t = 1.72
answer: sales tax = $1.72</span>
Answer:
m∠ABG = 20 degrees
m∠BCA = 22 degrees
m∠BAC = 118 degrees
m∠BAG = 59 degrees
DG = 4
BE = 12.4
BG = 11.7
GC = 20.4
Step-by-step explanation:
The given parameters are;
m∠CBG = 20°, m∠BCG = 11°
The incenter of a triangle is the point where the three bisectors of ΔABC meets
m∠ABG = m∠CBG = 20° by definition of angle bisector
m∠ABG = 20°
m∠ACG = m∠BCG = 11° by definition of angle bisector
m∠BCA = m∠ACG + m∠BCG = 11° + 11° = 22°
m∠ABC = m∠ABG + m∠CBG = 20° + 20° = 40°
m∠BAC = 180° - (m∠BCA+m∠ABC) = 180° - (40° + 22°) = 118°
m∠BAG = m∠CAG by definition of angle bisector
m∠BAC = 118° = m∠BAG + m∠CAG = m∠BAG + m∠BAG = 2 × m∠BAG
2 × mBAG = 118°
m∠BAG = 118°/2 = 59°
m∠BAG = 59°
Given that "G" is the incenter of the triangle ABC, we have;
GF = GE = DG = The radius of the incircle of the triangle = 4
Therefore, by Pythagoras' theorem, we have;
BG = √(11² + 4²) = √137 ≈ 11.7
BE = √((BG)² + 4²) = √(137 + 4²) = √153 ≈ 12.4
GC = √(20² + 4²) = √416= 4·√26 ≈ 20.4
<em>The answer to your problem is:</em>
x = 1/6
Answer:
256 and 14, 24, 16, 18
Step-by-step explanation:
16 X 32 ft Rectangle 6 inch round corners Inground Pool Basic Package, everything ... 35 Small Backyard Swimming Pool Designs Ideas You'll Love - homelovers
Answer:
<em><u>Note: I'm not sure all of this is correct</u></em> O_o
Part A
- Male IQR = Q₃ - Q₁ ≈ 15 - 5 ≈ 10
- Female IQR = Q₃ - Q₁ ≈ 9 - 2 ≈ 7
Part B
- Male Median = Q₂ ≈ 9 to 10
- Female Median = Q₂ ≈ 6 to 7
Difference ≈ 10 - 7 or 10 - 6 ≈ 3 to 4
Part C
<em>Male data distribution</em>
- <u>Shape</u>: The distribution is skewed right.
- <u>Outliers</u>: There doesn't appear to be any clear outliers on the box-plot.
- <u>Center</u>: Because the data is skewed, use median because it's a resistant measure of center. The median appears to be around 9 to 10.
- <u>Spread</u>: Because the data is skewed, use IQR because it's a resistant measure of spread. The IQR is calculated by subtracting the third quartile from the first quartile and appears to be around 10.
<em>Female data distribution</em>
- <u>Shape</u>: The distribution is slightly skewed right, but appears to have more normality than the male distribution
- <u>Outliers</u>: There appears to be one significant outliers at around 30 to 35 that is greatly larger than the rest of the data and is represented as a dot outside the box plot.
- <u>Center</u>: Because the data is skewed, use median because it's a resistant measure of center. The median appears to be around 6 to 7.
- <u>Spread</u>: Because the data is skewed, use IQR because it's a resistant measure of spread. The IQR is calculated by subtracting the third quartile from the first quartile and appears to be around 7.
Median would be a better measure of center for each because both data distributions aren't as symmetric/normal and have a skewed shape. Therefore, the median should be used because of its resistance, as it's not as impacted by extreme values as the mean.
Part D
There doesn't appear to be an outlier in the male dataset, but there appears to be a significantly large outlier in the female dataset, which might mean that there is a significantly large number of females(around 30 to 40) attending the latest superhero movie during a specific day of the study month. This might be due to a discount to the movie ticket that day for females, which attracts large number of females to watch the movie.