5 units; the following photo below is how I did solved it! Sry if you can’t understand my handwriting! Hope this helps!
Answer: The correct option is
(A) If F and G differ by a constant, then f = g.
Step-by-step explanation: According to the given condition, we have
![F'(x)=f(x)~~~\textup{and}~~~G'(x)=g(x).](https://tex.z-dn.net/?f=F%27%28x%29%3Df%28x%29~~~%5Ctextup%7Band%7D~~~G%27%28x%29%3Dg%28x%29.)
We are to select the correct statement.
Let F(x) = p(x) and G(x) = p(x) + c, c - constant.
Then, we get
![F'(x)=p'(x)~~~\textup{and}~~~G'(x)=p'(x).](https://tex.z-dn.net/?f=F%27%28x%29%3Dp%27%28x%29~~~%5Ctextup%7Band%7D~~~G%27%28x%29%3Dp%27%28x%29.)
Therefore,
![F'(x)=G'(x)\\\\\Rightarrow f(x)=g(x)\\\\\Rightarrow f=g.](https://tex.z-dn.net/?f=F%27%28x%29%3DG%27%28x%29%5C%5C%5C%5C%5CRightarrow%20f%28x%29%3Dg%28x%29%5C%5C%5C%5C%5CRightarrow%20f%3Dg.)
Thus, if F and G differ by a constant, then f = g.
Option (A) is CORRECT.
If a point bisects a segment, each line is congruent. So if UT is 4.5 yards TU would be 4.5 yards as well. UV is 9 yards
I would believe it to be 22
Answer:
ASA
Step-by-step explanation:
In given triangle
Line BC = Line QR
Angle ABC = Angle PQR
Angle ACB = Angle PRQ
Computation:
Angle ABC = Angle PQR (Angle)
Line BC = Line QR (Side)
Angle ACB = Angle PRQ (Angle)
So,
ΔABC ≅ ΔPQR
By Angle Side Angle property
ASA