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3 years ago

Waste reduction + rationalization of consumption + reuse + recycling / ways of preserving natural resources

Physics

1 answer:

forsale [732]3 years ago

5 0

Answer:

Hello your question is vague hence I will provide a general answer on the importance of : Waste reduction, rationalization of consumption, reuse, recycling as ways of preserving the natural resources

answer :

Waste reduction : when we reduce the amount of wastage on items we use especially items produced from natural raw materials we will help preserve the natural resource because they can be used to produce varieties of other items

Reuse and recycling of waste products help keep our natural environment healthy thus preserving our natural resources.

Explanation:

Waste reduction, rationalization of consumption, reuse and recycling are all ways of preserving our natural resources

Reuse and recycling of waste products help keep our natural environment healthy thus preserving our natural resources.

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During exercise, the amount of ____________ carried in the blood to the muscles increases.

ipn [44]

<span>The correct answer is: Oxygen

Explanation:
In order to function properly (movement etc.) during exercise, muscles require oxygen. During exercise, the depth as well as the rate of breathing increase, which in turn increases the amount of oxygen inhaled. In order to expand and contract lungs and for other bodily movements, muscles require oxygen, and for that, more oxygen is carried in the blood to muscles. Hence, the correct answer is Oxygen.</span>

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3 years ago

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Where is the sun located in the galaxy?

GarryVolchara [31]

I think it's 3. within an outer arm

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3 years ago

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A 0.30 kg softball has a velocity of 15 m/s at an angle of 35 degrees below the horizontal just before making contact with the b

jarptica [38.1K]

Answer:

a) 5.03 kg m/s

b) 10.03 kg m/s

Explanation:

Hi!

Let us consider the origin of coordinates at the pitcher, and pointing directly towards the initial direction of the ball. Therefore, the angle of the velocity with respect to the x axis is -35° (below the horizontal).

The components of the initial momentum are:

px = (0.3 kg)(15 m/s) cos(-35° ) = 4.5 cos(-35° ) kg m/s = 3.69 kg m/s

py = 4.5 sin(-35° ) kg m/s = -2.581 kg m/s

The final momentum will be:

pfx = 0

pfy = - (20 m/s) (0.3 kg) = -6 m/s

And the difference in momentum is:

dpy = pfy - py = -3.419 kg m/s

dpx = pfx - px = -3.69 kg m/s

And its magnitude:

dp = √(dpy^2 + dpx^2) = 5.03 kg m/s

pfx = -6 kg m/s

pfy = 0

And the difference in momentum is:

dpx = pfx - px = -9.69 kg m/s

dpy = pfy - py = 2.581 kg m/s

And its magnitude:

dp = √(dpy^2 + dpx^2) = 10.03 kg m/s

6 0

3 years ago

How many stars are in the universe (approximately)? O 40 sixtillion 0 365 billion O 86.4 million O one

Annette [7]

Answer:

a i belive

Explanation:

the univerce is VERY large so a, if im wrong i apologise :(

6 0

3 years ago

Assume you have a person with a mass of 65 kg riding a skateboard down a ramp. While they are

aliina [53]

Answer:

a) Eg = 3,060.72 j

b) Ek = 2,080 j

c) Etotal = 5,140.72 j

Explanation:

The given parameters are;

The mass of the person, m = 65 kg

The height of the person, h = 4.8 m

The speed of the person, v = 8.0 m/s

a) The gravitational potential energy, $E_g$ = m·g·h

Where;

g = The acceleration due to gravity ≈ 9.81 m/s²

∴ Eg = 65 kg × 9.81 m/s² × 4.8 m = 3,060.72 j

Eg = 3,060.72 j

b) The kinetic energy, Ek = 1/2·m·v²

∴ Ek = 1/2 × 65 kg × (8.0 m/s)² = 2,080 j

Ek = 2,080 j

c) The constant total Mechanical Energy, Etotal = Eg + Ek

∴ Etotal = 3,060.72 j + 2,080 j = 5,140.72 j

Etotal = 5,140.72 j.

8 0

3 years ago