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Ede4ka [16]
3 years ago
5

Following are the different layers of the sun’s atmosphere. Rank them based on the order in which a probe would encounter them w

hen traveling from earth to the sun’s surface
Physics
1 answer:
blsea [12.9K]3 years ago
6 0

Answer:

Going from earth to the sun a probe would encounter the next layers in order:

  • Corona
  • Transition Region
  • Chromosphere
  • Photosphere
  • Convection Zone
  • Radiative Zone
  • Core

A brief description of them:

Corona is the outermost layer and it cannot  be seen with the naked eye, is starts at about 2100 km from the surface of the sun and it has no limit defined.

Transition Region is between the corona and the chromosphere, it has an extension of about 100km

The chromosphere is between 400 km from the surface of the sun to 2100 km. In this layer the further you get away from the sun it gets hotter.

The photosphere is the surface of the sun, the part that we can see, and extends from the surface to 400km.

The convection zone is where convection happens, hot gas rises, cools and rises again.

Radiative Zone is where the photons try to rise to move to higher layers.

The core of the Sun is where nuclear fusion occurs due to the very high temperatures.

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Leokris [45]
They have the same Number of protons
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3 years ago
Physics problem: piston? The piston of a hydraulic automobile lift is 0.300 m in diameter. 1. What gauge pressure, in pascals, i
k0ka [10]
Pressure is given by:
P=F/A
force=1200*10=12000 N
Area=pi*r^2=3.14*0.15^2
=0.07065 m^2
Thus;
P=12000/0.7065
P=169,851.38 N/m^2
but
1 N/m^2=1 Pa
thus our pressure is:
169,851.38 Pa
3 0
3 years ago
Read 2 more answers
Calculate the force between two objects that have masses of 70 Kilograms and 2,000 kilograms separated by a distance of 1 meter
Hunter-Best [27]

9.3 x 10⁻⁶N

Explanation:

Given parameters:

Mass 1 = 70kg

Mass 2 = 2000kg

distance = 1m

Unknown:

force between them =  

Solution:

The force between the two masses will be a gravitational force of attraction.

  F = \frac{G m_{1}m_{2}  }{r^{2} }

 G is universal gravitation constant = 6.67430×10−¹¹ N⋅m²/kg²

 r is the distance between the two masses

Substituting the parameters:

 F = \frac{6.67 x 10^{-11} x 70 x 2000}{1^{2} } = 9.3 x 10⁻⁶N

 Learn more:

Universal gravitation constant   brainly.com/question/1724648

#learnwithBrainly

5 0
3 years ago
What is the weight of a<br> 63.7 kg person?
IRINA_888 [86]

Answer:

A person that weighs 63.7 kg weighs 63.7 kg

Explanation:

Too complicated to explain.

6 0
3 years ago
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A block with mass m is pulled horizontally with a force F_pull leading to an acceleration a along a rough, flat surface.
Simora [160]

Answer:

\mu_k=\frac{a}{g}

Explanation:

The force of kinetic friction on the block is defined as:

F_k=\mu_kN

Where \mu_k is the coefficient of kinetic friction between the block and the surface and N is the normal force, which is always perpendicular to the surface that the object contacts. So, according to the free body diagram of the block, we have:

N=mg\\F_k=F=ma

Replacing this in the first equation and solving for \mu_k:

ma=\mu_k(mg)\\\mu_k=\frac{a}{g}

6 0
3 years ago
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