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Alexeev081 [22]
3 years ago
12

-112128in standard form is​

Mathematics
1 answer:
Komok [63]3 years ago
3 0

Answer:

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On Sunday, Sheldon bought 4 1/2 kg of plant food. He used 1 2/3 kg on his strawberry plants and used 1/4 kg for his tomato plant
VladimirAG [237]

Answer:

a) 2\frac{7}{12} kg of plant food did Sheldon have left.

b) She need is \frac{43}{12} kg and she don't have enough to left.

Step-by-step explanation:

Given : On Sunday, Sheldon bought 4\frac{1}{2} kg of plant food. He used 1\frac{2}{3} kg on his strawberry plants and used \frac{1}{4} kg for his tomato plants.

To find :

a) How many kilograms of plant food did Sheldon have left? Write one or more equations to show how you reached your answer.

Solution :

Sheldon bought plant food 4\frac{1}{2}=\frac{9}{2} kg.

He used strawberry plants 1\frac{2}{3}=\frac{5}{3} kg.

He used tomato plants \frac{1}{4} kg

Kilograms of plant food did Sheldon have left is given by,

L=\frac{9}{2}-(\frac{5}{3}+\frac{1}{4})

L=\frac{9}{2}-\frac{23}{12}

L=\frac{54-23}{12}

L=\frac{31}{12}

L=2\frac{7}{12}

Therefore, 2\frac{7}{12} kg of plant food did Sheldon have left.

b) Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time. He will use the same amounts of plant food as before. How much plant food will he need? Does he have enough left to do so?

Solution :

Sheldon wants to feed his strawberry plants 2 more times.

i.e. Strawberry plants used is 2(\frac{5}{3})=\frac{10}{3} kg.

His tomato plants one more time i.e. \frac{1}{4} kg.

Total plant she need is \frac{10}{3}+\frac{1}{4}=\frac{43}{12}

As \frac{31}{12}

No she don't have enough to left.

4 0
3 years ago
What is y=-11x-8 in standard form?
djverab [1.8K]
<span>y=-11x-8
11x + y = -8 ...this is standard form

hope it helps</span>
4 0
3 years ago
Read 2 more answers
Matter is in a liquid state when its temperature is between its melting point and its boiling point. Suppose that some substance
a_sh-v [17]

Answer:

i. When the temperature is above 616.712^{o}F, it changes to gas.

ii. When the temperature is below -33.052^{o}F, it changes to solid.

Step-by-step explanation:

Matter generally exists in either a solid, liquid or gaseous form. With each phase having a certain range of temperature.

Temperature scale of a given substance can be either in Celsius, Fahrenheit or Kelvin. And conversion from one scale to another can be achieved. Example, Celsius scale can be converted to Fahrenheit by:

F = \frac{9}{5} θ + 32

where: F is the equivalent temperature in Fahrenheit, θ is the value of temperature in degree Celsius.

Given that: melting point of the substance = -36.14^{o}C

⇒ F =  \frac{9}{5} x -36.14^{o} + 32

      = -33.052^{o}F

The boiling point = 324.84^{o}C

F =  \frac{9}{5} x  324.84^{o} + 32

  = 616.712^{o}F

The melting point of the substance is -33.052^{o}F, and boiling point is 616.712^{o}F.

Therefore, the range of temperatures for which the substance is not in a liquid state are:

i. When the temperature is above 616.712^{o}F, it changes to gas.

ii. When the temperature is below -33.052^{o}F, it changes to solid.

3 0
3 years ago
Fill in the blanks to find the quotient 5/8 divided by 3 3/4 . Give the quotient as a fraction in simplest form.
Natali5045456 [20]

Answer:

Step-by-step explanation:

(5/8)/(3+3/4)

(5/8)/(15/4)

(5/8)(4/15)

20/120

1/6

4 0
3 years ago
Simplify the expression:<br> 2(2 + 7b) =
nikitadnepr [17]

Answer:

4 + 14b

Step-by-step explanation:

First, you need to distribute so,

2*2= 4   and

2*7b= 14b

4 0
3 years ago
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