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MariettaO [177]
3 years ago
12

Write an algebraic expression for the following statement: 9 times m increase by 6

Mathematics
1 answer:
Ierofanga [76]3 years ago
3 0

Answer: 9m+6

Step-by-step explanation: 9×m=9m and increase by 6= +6 so the answer is 9m+6

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What is the common difference between the elements of the arithmetic sequence below? –18, –22.5, –27, –31.5, –36
klasskru [66]
<span><u>Answer </u>
Common difference = -4.5

<u>Explanation. </u>
An arithmetic sequence is a sequence in which the next term is found by adding a constant to the current term. This constant is called the common difference.
If a, b, c, d, e, ….is an arithmetic sequence, then the common difference will be,
Common difference = b-a=c-b=d-c=e-d…..
Now the question above common difference is;
Common difference = (-22.5)-(-14)=-4.5 
</span>
4 2
3 years ago
1.
Mumz [18]

Answer:

B. P′ (−4, 0)

Step-by-step explanation:

You can look at the graph. The X-axis always goes first. SO -4 is first because it's on the x-axis. ANSWER= (-4, 0)

7 0
3 years ago
What’s the algebraic expression of y-2
krok68 [10]

Answer:

The algebraic expression for y -2 if this is subtraction is "some number" minus 2

Step-by-step explanation:

5 0
2 years ago
What are the x-intercepts of the graph of the function below? y=x^2+2x-15
ikadub [295]

Answer:

x=3  and x=-5

Step-by-step explanation:

To find the x intercepts set y =0 and solve for x

0 = x^2+2x-15

Factor

What two numbers multiply to -15 and add to 2

5*-3 = -15

5+-3 =2

0 = (x+5) (x-3)

Using the zero product property

x+5=0   x-3 =0

x=-5      x=3

6 0
4 years ago
Read 2 more answers
An open-top box is to be made from a 70-centimeter by 96-centimeter piece of plastic by removing a square from each corner of th
elixir [45]

Answer:

177 \frac{7}{9} cm^2

Step-by-step explanation:

Length of the Plastic Sheet= 96cm

Width of the plastic Sheet =70cm

If a square of side x is cut from each corner of the plastic sheet to form the box.

Length of the box=96-2x

Width of the box=70-2x

Height of the box =x

Volume of the box = LWH

Volume=(96-2x)(70-2x)x

The maximum volume of the box is obtained at the point where the derivative is zero.

V=(96-2x)(70-2x)x\\V^{'}=4(x-42)(3x-40)

Setting the derivative to 0.

4(x-42)(3x-40)=0\\x-42=0\: 3x-40=0\\x=42\:or\: x=\frac{40}{3}

Since we are looking for the minimum value of x,

x=\frac{40}{3}\\\text{Area of the Square} = x^2\\=\frac{40}{3} X \frac{40}{3}\\=177 \frac{7}{9} cm^2

7 0
3 years ago
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