Answer:
The genotypic frequency = 1:1
The phenotypic frequency = 1:1
Explanation:
Given that:
The allele → R = Red beetles
The allele → B = Blue beetles
Since the gene color shows a codominant allele
The Red Beetle = RR
The blue beetles will be = BB
The heterozygous beetle will be = RB
∴
The punnet square showing the crossing of RB × RR is:
R B
R RR RB
R RR RB
The result shows that we have two red beetles and two heterozygous beetles.
Hence;
The genotypic frequency = 1:1
The phenotypic frequency = 1:1
Answer:
both can be found in all living things
Answer:
Animals, Humans, Oil, Gases, And Coal all contain Carbon Dioxide in our atomosphere.
Explanation:
Answer:
This composition of nucleotide given in the question do not obey the chargaff"s rule.
Explanation:
According to chargaff"s rule the total number of purine bases will be same to the total number of pyrimidine bases that is
Adenine+Guanine=Thymine+Cytosine
But here the above quation is not maintained because according to the question A+G=49%
and T+C = 51%.
Such DNA is replicated by rolling circle model.
