Answer:
The minimum value = -38
Step-by-step explanation:
∵ f(x) = x² - 12x - 2
∵ -12x ÷ 2 = -6x ⇒ -6 × x
∴ (x - 6)² = x² - 12x + 36
∴ Add and subtract 36 in f(x)
∴ f(x) = (x² - 12x + 36) - 36 - 2
∴ f(x) = (x - 6)² - 38 ⇒ completing square
∴ The vertex of the parabola is (6 , -38)
∵ Its minimum point because the coefficient of x² is positive
∴ The minimum value = -38
The length of each side of a square is 3 in. more than the length of each side of a smaller square. The sum of the areas of the squares is 149 in. $^{2} .$ Find the lengths of the sides of the two squares.
I think the answer would be 343?
Answer:
y = - 4x
Step-by-step explanation:
Here, it is given that the slope of a line is - 4 and the y-intercept is 0.
Now, if the slope of a straight line is m and the y-axis intercept is c, the by slope-intercept form the equation of the straight line is given as
y = mx + c ......... (1)
Therefore, in our case m = - 4 and c = 0 and using equation (1), the equation of the given straight line is
y = - 4x (Answer)
