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Marianna [84]
3 years ago
5

PLEASE HELP What percent of 64 is 4?

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
4 0

Answer:

6.25 is the answer

Step-by-step explanation:

hope this helps:P

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Graph the inverse circular function by hand, given f(x) = 3sin(2x) ;-pi/4 ≤ ≤pi/4
nasty-shy [4]

Part a)

a) The given function is

f(x) = 3 \sin(2x)

We let

y =  3 \sin(2x)

Interchange x and y.

x=  3 \sin(2y)

Solve for y;

\frac{x}{3}  =  \sin(2y)

y =  \frac{1}{2}  { \sin}^{ - 1}( \frac{x}{3} )

{f}^{ - 1}(x)  =  \frac{1}{2}  { \sin}^{ - 1}( \frac{x}{3} )

Part b) The range of f(x) refers to y-values for which f(x) exists.

The range of f(x) is

-  3 \leqslant y \leqslant 3

This is because the function is within y=-3 and y=3.

c) The range of

{f}^{ - 1} (x)

is

-  \frac{ \pi}{4}  \leqslant y \leqslant  \frac{\pi}{4}

The domain is -3≤x≤3

This is because the domain and range of a function and its inverse swaps.

Part d) The graph is shown in the attachment.

3 0
4 years ago
Find m angle 1 and m angle 3 in the kite.
stepladder [879]

Answer:

m∠1=39°, m∠3=51°

Step-by-step explanation:

Angle 3 = 180-(39+90)

180-129=51

Angle 1 = 39 b/c of the corresponding angles.

6 0
3 years ago
The population of a certain town was 10,000 in the year 2000 the town manager predicted that for the next 20 years the populatio
Bond [772]
The population of the town from 2000 to 2020 is modeled by the equation:

p(t)=10000(1.05)^{t}

Where t is the number of years since 2000.

We have to find the expected population of the town in 2002. The number of years from 2000 to 2002 are 2, so we have to find p(2). Replacing t by 2 in the above equation, we get:

p(2)=10000(1.05)^{2}  \\  \\ 
p(2)=11025

So, according to the model, the population of town in 2002 is predicted to be 11,025.
8 0
3 years ago
So here is a theoretical question. Let L1 and L2 be linear transformation from a vector space V into Vector space W. Let {v1,v2,
noname [10]
<span>if v belongs to V, then we can find scalars a1,a2,...,an, such that v=a1*v1+a2*v2+...+an*vn, L1(v)=L1(a1*v1+a2*v2+...+an*vn) =a1*L1(v1)+a2*L1(v2)+...+an*L1(vn) =a1*L2(v1)+a2*L2(v2)+...+an*L2(vn) =L2(a1*v1+a2*v2+...+an*vn) =L2(v)</span>
6 0
3 years ago
If the value of 2x to the third power is 2, then what is the value of x?
Stella [2.4K]

2x^2 = 2

so x needs to equal 1 since 2*1 = 2

7 0
4 years ago
Read 2 more answers
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