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VMariaS [17]
2 years ago
6

What are 2 similarities and 2 differences between photosynthesis and cellular respiration?

Biology
1 answer:
FrozenT [24]2 years ago
8 0

Answer:

Photosynthesis and respiration are biological reactions that complement each other in the environment. Both photosynthesis and cellular respiration cannot occur without the other. However, there are differences between photosynthesis vs. cellular respiration. Photosynthesis involves the use of energy from sunlight, water, and carbon dioxide to produce glucose and oxygen, whereas cellular respiration uses glucose and oxygen to produce carbon dioxide and water.

Respiration and photosynthesis are biological reactions in the environment that complement each other. Both are similar reactions that occur in a specific manner. In the process of respiration, oxygen and glucose yield water and carbon dioxide, while carbon dioxide and water yield glucose and oxygen during the process of photosynthesis.

Explanation:

Cellular Respiration

Cellular respiration is a set of metabolic reactions and processes that take place in the cells of organisms to convert chemical energy from oxygen molecules or nutrients into adenosine triphosphate (ATP), and then release waste products. The reactions involved in respiration are catabolic reactions, which break large molecules into smaller ones, releasing energy because weak high-energy bonds, in particular in molecular oxygen, are replaced by stronger bonds in the products. Respiration is one of the key ways a cell releases chemical energy to fuel cellular activity. The overall reaction occurs in a series of biochemical steps, some of which are redox reactions. Although cellular respiration is technically a combustion reaction, it clearly does not resemble one when it occurs in a living cell because of the slow, controlled release of energy from the series of reactions.

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Rudiy27

Answer:

A. C_2=1.5\frac{mg}{mL}

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C. C_2=0.01\frac{mg}{mL}

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Explanation:

Hello.

In this case, we must compute the final concentration in all the cases so we solve for it in the given equation:

C_2=\frac{C_1V_1}{V_2}

Thus, we proceed as follows:

A. Here, the final diluted solution includes the 300 μL of the 5 mg/ml-BSA and the 700 μL of TBS.

C_2=\frac{300\mu L*5\frac{mg}{mL} }{(300+700)\mu L}\\\\C_2=1.5\frac{mg}{mL}

B. Here, the final diluted solution includes the 50 μL of the 1.5 mg/ml-BSA, the 450 μL of water and the 500 μL of TBS.

C_2=\frac{50\mu L*1.5\frac{mg}{mL} }{(50+450+500)\mu L}\\\\C_2=0.075\frac{mg}{mL}

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C_2=\frac{10\mu L*1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.01\frac{mg}{mL}

D. Here, the final diluted solution includes the 10 μL of the 0.1 mg/ml-BSA and the 990 μL of TBS.

C_2=\frac{10\mu L*0.1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.001\frac{mg}{mL}

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