I believe the criteria responsible for deciding whether a heterogeneous mixture is a colloid or a suspension is whether the <span>particles remain suspended for an extended period of time. I hope it helps you.</span>
Becuase they need special equipment and things like that that may not be available in the state i think
The average atomic mass of the element is 204.40 amu
<h3>Average atomic mass and isotopic mass</h3>
- The average atomic mass of an element is the average mass of the atom of that element calculated from the isotopic masses of the atoms of that element and their percentage abundances
- Isotopic mass is the mass of each isotope of that element
<h3>Calculation of average atomic mass</h3>
Average atomic mass = sum of isotopic mass * abundance of each isotope
Average atomic mass = 202.99 * 29.524% + 70.476% * 204.99 amu.
Average atomic mass = 204.40 amu
Therefore, the average atomic mass of the element is 204.40 amu
Learn more about average atomic mass and isotopic mass at: brainly.com/question/11096711
Tonight I’m Doing homework :(
Answer:
38.36 L.
Explanation:
- We can use the general law of ideal gas: PV = nRT.
where, P is the pressure of H₂ in atm (P = 1.0 atm, STP conditions).
V is the volume of H₂ in L (V = ??? L).
n is the no. of moles of H₂ in mol (n = mass/molar mass = (10.0 g)/(2.0 g/mol) = 5.0 mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K),
T is the temperature of H₂ in K (T = 0.0°C + 273 = 273.0 K, STP conditions).
<em>∴ V = nRT/P</em> = (5.0 mol)(0.0821 L.atm/mol.K)(273.0 K)/(1.0 atm) = <em>38.36 L.</em>