Answer:
1.2 mL
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated:
HCl + KOH —> KCl + H₂O
From the balanced equation,
Mole ratio of the acid, HCl (nₐ) = 1
Mole ratio of base, KOH (n₆) = 1
Finally, we shall determine the volume of the base, KOH needed to neutralize the acid, HCl as follow:
Molarity of base, KOH (M₆) = 0.997 M
Volume of acid, HCl (Vₐ) = 30 mL
Molarity of acid, HCl (Mₐ) = 0.0400 M
Volume of base, KOH (V₆) =?
MₐVₐ / M₆V₆ = nₐ/n₆
0.04 × 30 / 0.997 × V₆ = 1/1
1.2 / 0.997 × V₆ = 1
Cross multiply
0.997 × V₆ = 1.2
Divide both side by 0.997
V₆ = 1.2 / 0.997
V₆ = 1.2 mL
Thus, the volume of the base, KOH needed to neutralize the acid is 1.2 mL.
