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Hatshy [7]
3 years ago
8

A bar of copper has a mass of 216g and a volume of 24cm^3. What is the density of copper?

Chemistry
1 answer:
7nadin3 [17]3 years ago
3 0

Answer:

<h2>The answer is 9 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 216 g

volume = 24 cm³

The density is

density  =  \frac{216}{24}   \\

We have the final answer as

<h3>9 g/cm³</h3>

Hope this helps you

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How much energy is required to raise the temperature of 10.7 grams of gaseous helium from 22.1 °C to 39.4 °C ?
Rainbow [258]

Answer:

Q = 2640.96 J

Explanation:

Given data:

Mass of He gas = 10.7 g

Initial temperature = 22.1°C

Final temperature = 39.4°C

Heat absorbed = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree. Specific heat capacity of He is 14.267 J/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 39.4°C - 22.1°C

ΔT = 17.3°C

Q = 10.7 g× 14.267 J/g.°C ×  17.3°C

Q = 2640.96 J

5 0
3 years ago
In any chemical compound, the elements are always combined in the same proportion by ___.?
irga5000 [103]

Answer is: elements are always combined in the same proportion by mass.

Law of multiple proportions or Dalton's Law said that the ratios of the masses of the second element which combine with a fixed mass of the first element will be ratios of small whole numbers.

For example, nitrogen(I) oxide N₂O; m(N) : m(O) = 2·14 : 16 = 7 : 4.

Another example, water (H₂O) is made of two hydrogen atoms and one oxygen atom:  

m(H) : m(O) = 2·1 : 16 = 1: 8.

6 0
3 years ago
Read 2 more answers
A 25.0 g sample of an alloy was heated to 100.0 oC and dropped into a beaker containing 90 grams of water at 25.32 oC. The tempe
kaheart [24]

Answer:

The specific heat of the alloy C_{a} = 0.37 \frac{KJ}{Kg K}

Explanation:

Mass of an alloy m_{a} = 25 gm

Initial temperature T_{a} = 100°c = 373 K

Mass of water m_{w} = 90 gm

Initial temperature of water T_{w} = 25.32 °c = 298.32 K

Final temperature T_{f} = 27.18 °c = 300.18 K

From energy balance equation

Heat lost by alloy = Heat gain by water

m_{a} C_{a}  [T_{a} - T_{f}] = m_{w} C_w (T_{f} -T_{w} )

25 × C_{a} × ( 373 - 300.18 ) = 90 × 4.2 (300.18 - 298.32)

C_{a} = 0.37 \frac{KJ}{Kg K}

This is the specific heat of the alloy.

6 0
3 years ago
Walter was heating some cubes of ice while conducting an experiment. At one point, the ice melted into water. What is the correc
tatiyna
This would be the Melting point because it is showing that at a certain heat it melts so therefore it is the point it melts and therefore called the melting point
7 0
3 years ago
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How many moles of butane do we have if we have 5.50 x 1024 molecules<br> of butane (CH) ?
Dmitry [639]

Answer:

9.14moles

Explanation:

Given parameters:

Number of atoms of butane  = 5.5 x 10²⁴atoms

Unknown:

Number of moles  = ?

Solution:

To solve this problem, we must understand that a mole of any substance contains the Avogadro's number of particles.

             6.02 x 10²³ atoms makes up 1 mole of an atom

             5.5 x 10²⁴ atoms will contain = \frac{5.5 x 10^{24} }{6.02 x 10^{23} }  = 9.14moles

7 0
2 years ago
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