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Sholpan [36]
2 years ago
13

7. Write the equation for the positron emission of barium-127.

Chemistry
1 answer:
ziro4ka [17]2 years ago
8 0

The reaction is given by

\\ \rm\Rrightarrow {}^{127}_{56}Ba\longrightarrow {}^{0}_{+1}\beta+{}^{127}_{55}Cs

Barium goes underneath beta decay to form Ceaseum

  • Cs is very mellable element
  • It can melt on your hand
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how many minutes does it take light from the sun to reach earth the distance from the sun to earth is 93 million mi the speed of
Tems11 [23]
Look to be honest, I don't know how to work out the problem, but my teacher, and my says it takes 8 minutes for the Sun's light to reach

hope my answer works :)
8 0
3 years ago
The balanced equation shows how sodium chloride reacts with silver nitrate to form sodium nitrate and silver chloride. NaCl + Ag
Verdich [7]
<span>NaCl First calculate the molar mass of NaCl and AgNO3 by looking up the atomic weights of each element used in either compound Sodium = 22.989769 Chlorine = 35.453 Silver = 107.8682 Nitrogen = 14.0067 Oxygen = 15.999 Now multiply the atomic weight of each element by the number of times that element is in each compound and sum the results For NaCl 22.989769 + 35.453 = 58.44277 For AgNO3 107.8682 + 14.0067 + 3 * 15.999 = 169.8719 Now calculate how many moles of each substance by dividing the total mass by the molar mass For NaCl 4.00 g / 58.44277 g/mol = 0.068443 mol For AgNO3 10.00 g / 169.8719 g/mol = 0.058868 Looking at the balanced equation for the reaction, there is a 1 to 1 ratio in molecules for the reaction. Since there is a smaller number of moles of AgNO3 than there is of NaCl, that means that there will be some NaCl unreacted, so the excess reactant is NaCl</span>
8 0
3 years ago
How much of 45 grams of pu 234 remains after 27 hours if it’s half life is 4.98 hours
nadya68 [22]

Answer:

1.07 g

Explanation:

Half-life of Pu-234 = 4.98 hours

Initially present = 45 g

mass remains after 27 hours = ?

Solution:

Formula

         mass remains = 1/ 2ⁿ (original mass) ……… (1)

Where “n” is the number of half lives

To find "n" for 27 hours

                          n = time passed / half-life . . . . . . . .(2)

put values in equation 2

                          n = 27 hr / 4.98 hr

                          n = 5.4

Mass after 27 hr

Put values in equation 1

          mass remains = 1/ 2ⁿ (original mass)

          mass remains = 1/ 2^5.4 (45 g)

          mass remains = 1/ 42.2 (45 g)

          mass remains =  0.0237 x 45 g

          mass remains =  1.07 g

6 0
3 years ago
A student wants to collect data during an experiment about the transfer of kinetic energy in a sample of water and ice. Which to
erastova [34]

Given what we know, the tool in question that will help the student collect data regarding the transfer of kinetic energy between water and ice would be a thermometer.

<h3>How does the thermometer measure kinetic energy?</h3>

It does not do so directly. However, kinetic energy in water molecules is reflected in the temperature of the water. When water molecules increase their kinetic energy and move more, they become hotter. Increased or decreased heat is an indirect way to measure the transfer of kinetic energy in water.

Therefore, given that the temperature of the water is a reflection of the transfer of kinetic energy happening, we can confirm that the tool that will help the student collect the data needed is a thermometer.

To learn more about kinetic energy visit:

brainly.com/question/999862?referrer=searchResults

3 0
2 years ago
What was the resulting molarity of your primary standard solution of potassium iodate kio3?
melamori03 [73]
Missing question: 0,535 gram of KIO₃ dissolved in 250 mL of de-ionized water to <span>make primary standard solution.
m(</span>KIO₃) = 0,535 g.
V(KIO₃) = 250 mL ÷ 1000 mL/L = 0,25 L.
n(KIO₃) = m(KIO₃) ÷ M(KIO₃).
n(KIO₃) = 0,535 g ÷ 214 g/mol.
n(KIO₃) = 0,0025 mol.
c(KIO₃) = n(KIO₃) ÷ V(KIO₃).
c(KIO₃) = 0,0025 mol ÷ 0,25 L.
c(KIO₃) = 0,01 mol/L = 0,01 M.
8 0
2 years ago
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