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Sholpan [36]
2 years ago
13

7. Write the equation for the positron emission of barium-127.

Chemistry
1 answer:
ziro4ka [17]2 years ago
8 0

The reaction is given by

\\ \rm\Rrightarrow {}^{127}_{56}Ba\longrightarrow {}^{0}_{+1}\beta+{}^{127}_{55}Cs

Barium goes underneath beta decay to form Ceaseum

  • Cs is very mellable element
  • It can melt on your hand
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Difference between Rapid and spontaneous composition​
Over [174]

Answer:

<em><u>spontaneous composition</u></em> is the ingnition

of the substance due to the repid oxidation of its on material.

There is no requirement of heat of external sources.

<em><u>Rapid composition</u></em> on the other hand release large amount of heat and light energy.

Explosion and the firecracker is the best example of Rapid composition.

3 0
4 years ago
Complete the sentences to explain what’s happening at different portions of the heating curve.
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Particles of the substance have the most kinetic energy when the substance is(a)1. A gas. The part of the graph that represents where the substance has the least amount of potential energy is labeled(b)1. Solid.

Gas molecules have the highest average velocities among the three states of matter so gas has the highest kinetic energy. During freezing, a substance loses a lot of potential energy so solid has the least potential energy.

9 0
4 years ago
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The earth rotates on an imaginary line called an?
Pavel [41]

Answer: An axis.

Explanation:

3 0
4 years ago
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Please review the attachment
astra-53 [7]

Answer: The correct answer is -297 kJ.

Explanation:

To solve this problem, we want to modify each of the equations given to get the equation at the bottom of the photo. To do this, we realize that we need SO2 on the right side of the equation (as a product). This lets us know that we must reverse the first equation. This gives us:

2SO3 —> O2 + 2SO2 (196 kJ)

Remember that we take the opposite of the enthalpy change (reverse the sign) when we reverse the equation.

Now, both equations have double the coefficients that we would like (for example, there is 2S in the second equation when we need only S). This means we should multiply each equation (and their enthalpy changes) by 1/2. This gives us:

SO3 —>1/2O2 + SO2 (98 kJ)

S + 3/2O2 —> SO3 (-395 kJ)

Now, we add the two equations together. Notice that the SO3 in the reactants in the first equation and the SO3 in the products of the second equation cancel. Also note that O2 is present on both sides of the equation, so we must subtract 3/2 - 1/2, giving us a net 1O2 on the left side of the equation.

S + O2 —> SO2

Now, we must add the enthalpies together to get our final answer.

-395 kJ + 98 kJ = -297 kJ

Hope this helps!

8 0
3 years ago
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What is the answer please tell me
Nastasia [14]

Answer:

you need to include the bottom portion, not enough info

Explanation:

5 0
3 years ago
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