Answer:
These organelles are like the organs in a human and they help the cell stay alive. Each organelle has it's own specific function to help the cell survive. The nucleus of a eukaryotic cell directs the cell's activities and stores DNA. ... All of the cell's organelles must work together to keep the cell healthy.
Explanation:
These organelles are like the organs in a human and they help the cell stay alive. Each organelle has it's own specific function to help the cell survive. The nucleus of a eukaryotic cell directs the cell's activities and stores DNA. ... All of the cell's organelles must work together to keep the cell healthy.
In the amtmosphere this water vapor cools and turns back to liquid for forming clouds
this process is called condensation. When it cant hold on much longer it will turn into rain or snow.
Answer: The mass of blue copper sulfate is 3.5 g
Explanation:
Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.
This also means that total mass on the reactant side must be equal to the total mass on the product side.
The chemical equation for the heating of copper sulfate crystals is:
Let the mass of blue copper sulfate be 'x' grams
We are given:
Mass of copper sulfate powder = 2.1 grams
Mass of water = 1.4 grams
Total mass on reactant side = x
Total mass on product side = (2.1 + 1.4) g
So, by applying law of conservation of mass, we get:
Hence, the mass of blue copper sulfate is 3.5 grams
Answer:
-152.92°C
Explanation:
Initial volume = 0.750 mL
Initial temperature = -32.7 °C (-32.7 + 273.15 K = 240.45 k)
Final temperature = ?
Final volume = 0.750 mL / 2= 0.375 mL
Solution:
The given problem will be solve through the Charles Law.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₂ = T₁V₂ / V₁
T₂ = 240.45 k × 0.375 mL / 0.750 mL
T₂ = 90.17 mL.K / 0.750 mL
T₂ = 120.23 K
Temperature in celsius:
120.23 K - 273.15 = -152.92°C
Answer:
79'420J
Explanation:
We know mass 250g and
∆T=98°C -22°C
=76°C
The specific heat capacity for water is 4,18Zj/g°C
THEREFORE
∆H=250g•14,8j/g°C •76°C
=79'420J