First what you do is divide 14 by 4 and you get 3.5 or 3 feet and 6 inches.
142.8
it fizzes up and shoots out
88
Answer:
-3
Step-by-step explanation:
Step 1: Solve (-2+(-1))^2/3 3
1. -2+(-1) = -3
2. (-3)^2 = 9
3. 9/3 = 3
Step 2: Solve (-4)^2-17 -1
1. 3/-1
Step 3: Simplify 3/-1 = -3. I hope this helped and please don't hesitate to reach out with more questions!
Answer:
x = 7.5
Step-by-step explanation:
Since DF bisects ∠CDE then
∠EDF = ∠CDF, hence
8x = 4x + 30 ( subtract 4x from both sides )
4x = 30 ( divide both sides by 4 )
x = 7.5
This is like a triangle.
One side, the hypotenuse, is the length of the ladder, 10 feet in this case.
Another side, one of legs, is the distance from the bottom of the ladder to the side of the wall, 6 feet.
The last side is what we need to find, how high up the ladder reaches.
Using the p<span>ythagorean theorem, we can find this third side.
This is written as a^2 + b^2 = c^2.
A and B are the legs, while C is the hypotenuse.
Plugging in known values, we get:
6^2 + b^2 = 10^2
Solve as much as possible:
6^2 = 36
10^2 = 100
36 + b^2 = 100
Now you must isolate b.
Subtract 36 from both sides.
100 - 36 = 64
b^2 = 64
The last step in finding b is doing the inverse of squaring, which is square rooting.
√64 = 8
So b equals 8.
This means that <span>the ladder can reach 8 feet up the wall.</span></span>
