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mylen [45]
3 years ago
14

What is the solution of this system of linear equations? 3y = 3 y equals StartFraction 3 over 2 EndFraction x plus 6.X + 6 y – S

tartFraction one-half EndFraction y minus StartFraction 1 over 4 EndFraction x equals 3.X = 3 (3, 6) (2, 1) no solution infinite number of solutions
Mathematics
2 answers:
Gennadij [26K]3 years ago
6 0

The solution of the given system of equation is \boxed{\bf (0,6)}.

Further explanation:

The given system of equations is as follows:

\boxed{\begin{aligned}y&=\dfrac{3}{2}x+6\\ \dfrac{y}{2}-\dfrac{x}{4}&=3\end{aligned}}

Label the above equations as follows:

y&=\dfrac{3}{2}x+6                                      ......(1)

\dfrac{y}{2}-\dfrac{x}{4}&=3                         ......(2)

To obtain the solution of the given system of equation use the substitution method.

Substitute the expression y&=\frac{3}{2}x+6 in equation (2) to obtain the value of x.

\begin{aligned}\dfrac{1}{2}\left(\dfrac{3}{2}x+6\right)-\dfrac{x}{4}&=3\\\dfrac{3}{4}x+3-\dfrac{x}{4}&=3\\\dfrac{3x-x}{4}+3-3&=0\\\dfrac{2x}{4}&=0\\x&=0\end{aligned}

Therefore, the value of x is 0.

Substitute 0 for x in equation (1) to obtain the value of y.

\begin{aligned}y&=\left(\dfrac{3}{2}\cdot 0\right)+6\\&=6\end{aligned}

Therefore, the value of y is 6.

From the above calculation it is concluded that the solution of the given system of equation is (0,6).

Thus, the solution of the given system of equation is \boxed{\bf (0,6)}.

Learn more:

1. A problem on composite function brainly.com/question/2723982  

2. A problem to find radius and center of circle brainly.com/question/9510228  

3. A problem to determine intercepts of a line brainly.com/question/1332667  

Answer details:

Grade: High school

Subject: Mathematics

Chapter: Linear equation

Keywords: Equation, linear equation, degree 1, higest power 1, system of linear equation, solution set, solution, mathematics, substitution method, consistent system , inconsistent system.

Scrat [10]3 years ago
3 0

Answer:

(0,6)

Step-by-step explanation:

The given system of equations is

y =  \frac{3}{2}x + 6

and

\frac{1}{2}y -  \frac{1}{4}x = 3

We substitute the first equation into the second equation to get:

\frac{1}{2} ( \frac{3}{2}x + 6) -  \frac{1}{4}x = 3

We expand to get:

\frac{3}{4} x + 3 -  \frac{1}{4}x = 3

We group similar terms to get:

\frac{3}{4}x -  \frac{1}{4}x = 3 - 3

\frac{1}{2}x = 0

x = 0

Put x=0 in to the first equation to get:

y = 6

Therefore the solution is (0,6)

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On a coordinate plane, a parabola opens up.

Solid circles appear on the parabola at (negative 4, 14), (negative 3, 9. 5), (negative 2, 6), (0, 2), (1, 1. 5), (2, 2), (4, 6), (5, 9. 5), (6, 14).

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