Part A) Find BC, the distance from Tower 2 to the plane, to the nearest foot.
in the triangle ACD
sin16=CD/(7600+BD)--------> CD=sin16*(7600+BD)---------> equation 1
in the triangle BCD
sin24=CD/BD-----------> CD=sin24*BD---------------> equation 2
equation 1=equation 2
sin16*(7600+BD)=sin24*BD-----> sin16*7600+sin16*BD=sin24*BD
sin24*BD-sin16*BD=sin16*7600----> BD=[sin16*7600]/[sin24-sin16]
BD=15979 ft
in the triangle BCD
cos24=BD/BC---------> BC=BD/cos24-------> 15979/cos24-------> 17491
BC=17491 ft
the answer part 1) BC is 17491 ft
Part 2) Find CD, the height of the plane from the ground, to the nearest foot.
CD=sin24*BD ( remember equation 2)
BD=15979 ft
CD=sin24*15979 -----------> CD=6499 ft
the answer part 2) CD is 6499 ft
Answer:2,2
Step-by-step explanation:
I remember doing this last year
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Answer:
x = 107 , y = 60
Step-by-step explanation:
Each lower base angle is supplementary to the upper base angle on the same side, then
x + 73 = 180 ( subtract 73 from both sides )
x = 107
and
y + 2y = 180
3y = 180 ( divide both sides by 3 )
y = 60
probability = favourable outcomes/total outcomes
you need 1 banana, out of 4 and there are total of 6 items so probability will be 4/6
when you take out 1 banana, there are 3 banana left and total of 5 items
so probability of this action will be 3/5
now, next action is taking out another banana.
this is NOT an independent event.
so by we will multiply the probabilities of these events according to rule of products.
so the answer is 
or 2×100/5=40%
