<span>Answer: 0.070 m/s
Explanation:
1) balanced chemical equation:
given: 2HBr(g) → H2 (g)+Br2(g)
2) Mole ratios:
2 mol HBr : 1 mol H2
3) That means that every time 2 moles of HBr disappear 1 mol of H2 appears.
That is, the H2 appears at half rate than the HBr disappears.
∴ rate of appearance of H2 = rate of disappearance of HBr / 2 = 0.140 m/s / 2 = 0.070 m/s, which is the answer.</span>
i'm pretty sure the answer you chose is correct
Answer:
47.5 g of water can be formed
Explanation:
This is the reaction:
CH₄ + 2O₂ → CO₂ + 2H₂O
Methane combustion.
In this process 1 mol of methane react with 2 moles of oxygen to produce 2 moles of water and 1 mol of carbon dioxide.
As ratio is 1:2, I will produce the double of moles of water, with the moles of methane I have.
1.320 mol .2 = 2.64 moles
Now, we can convert the moles to mass (mol . molar mass)
2.64 mol . 18g/mol = 47.5 g
A,D,and E I hope this helps
Answer:
Explanation:
You need the conversion factor to convert the value of 12.33 kPa to milimiters of mercury, mmHg.
The converstion factors are looked at tables, which today you can find in internet.
Since the conversions between kPa and atm and between atm and mmHg are more widely known, I will show the conversion using those relations:
⇒ 101.325 kPa = 760 mmHg
Then, dividing both sides by 101.325 kPa you get the conversion factor:
- 1 = 760 mmHg / 101.325 kPa
Now, multiply 12.33 kPa by that conversion factor:
- 12.33 kPa × 760 mmHg / 101.325 kPa = 92.48 mmHg ← answer
