<span>For that we need to know something about the chemistry aluminum sulfide and aluminum hydroxide. Aluminum sulfide will react with water to make insoluble aluminum hydroxide and hydrogen sulfide gas. Therefore, we need a balanced chemical equation.
Al2S3(s) + 6HOH --> 2Al(OH)3(s) + 3H2S(g)
17.7g ........................ ???g
17.7g Al2S3 x (1 mol Al2S3 / 150.3 g Al2S3) x (2 mol Al(OH)3 / 1 mol Al2S3) x (78.0g Al(OH)3 / 1 mol Al(OH)3) = 18.4 g Al(OH)3 ...... to three significant digits.</span>
Answer:
#1 is protons electrons and neutrons
their respective parts are center, positive ,and no charge
#2 is positive charge, chemical properties
#3 is the number of protons, characteristics, same
#4 is atomic mass, average atomic mass
#5 is mass number, nucleus
Explanation:
no need to say thank tou i know ur in class
Answer:
1)NH4ClO4: acidic
2)NH4CN: basic
3)LiF: basic
4)KCN: basic
5)LiNO3: neutral
6)NH4Br: acidic
7)SrBr2: neutral
Explanation:
Salt is an ionic compound formed by the neutralization reaction between an acid and a base.The cation of base and anion from an acid combines to form a salt while H+ from acid and OH- from base forms water.
1)NH4Cl4: is an acidic salt formed from neutralization reaction between strong acid and a weak base.
2)NH4CN: is a basic salt formed from neutralization reaction between weak acid and weak base.
3)LiF: basic salt formed from neutralization reaction between strong acid and strong base.
4)KCN: basic salt formed from neutralization reaction between weak acid and strong base.
5)LiNO3: neutral salt formed from neutralization reaction between strong acid and strong base.
6)NH4Br: acidic salt formed from neutralization reaction between strong acid and weak base.
7)SrBr2: neutral acid formed from neutralization reaction between
strong acid and strong base.
Quarts of pure antifreeze must be added to 5 quarts of a 20 antifreeze solution to obtain a 50 antifreeze solution is 3.
Antifreeze solution is a solute that lowers the freezing point of the liquid in a solution.
For calculating the amount of quarts of pure antifreeze solution added can be given by:
5×20/100 + x × 100% = (x+5) × 50/100
Where, x is the amount of antifreeze required for addition and pure antifreeze is 100% of the antifreeze taken.
1 + x = (x+5) 0.5
1 + x = 0.5x + 2.5
0.5x = 1.5
x = 3
So, 3 quarts of pure antifreeze must be added to 5 quarts of a 20 antifreeze solution to obtain a 50 antifreeze solution.
Learn more about Antifreeze solution here, brainly.com/question/14619701
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Answer:
r = k.[NO₂]²
Explanation:
Let's consider the following reaction.
NO₂ + CO → NO + CO₂
A generic rate law is:
r = k.[A]ᵃ.[B]ᵇ
where,
r is the reaction rate
k is the rate constant
[A] and [B] are the molar concentrations of the reactants
a and b are the reaction orders with respect to A and B, respectively
The reaction is second order in NO₂ and zero order in CO. The corresponding rate law is:
r = k.[NO₂]².[CO]⁰
r = k.[NO₂]²
