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devlian [24]
3 years ago
11

A chemical reaction has an increase in entropy and a decrease in enthalpy. what is known about the spontaneity of the reaction?

spontaneous at high temperatures, nonspontaneous at low temperatures nonspontaneous at high and low temperatures spontaneous at low temperatures, nonspontaneous at high temperatures spontaneous at high and low temperatures
Chemistry
2 answers:
Kobotan [32]3 years ago
4 0
I think the correct answer would be the first option. A chemical reaction that has an increase in entropy and a decrease in enthalpy is spontaneous at high temperatures. This reaction absorbs heat for it to occur so supplying heat to it is important. 
DanielleElmas [232]3 years ago
4 0

Answer: spontaneous at high and low temperatures

Explanation: \Delta G=\Delta H-T\Delta S

\Delta G = Gibb's free energy change

\Delta H= enthalpy change

T = temperature

\Delta S = entropy change

A reaction is spontaneous when \Delta G = Gibb's free energy change is negative.

Given \Delta H= decrease in enthalpy = -ve

\Delta S = increase in entropy = +ve

Thus \Delta G=(-\Delta H)-T(+\Delta S)

\Delta G=-(\Delta H)-T(\Delta S)=-ve

As  \Delta G is always negative, it is spontaneous at all the temperatures.


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Gala2k [10]

Answer:

Alright the very first thing you need to do is balance the equation:

2HCl + Na2CO3 -----> 2NaCl + CO2 + H2O

Now we need to find the limiting reactant by converting the volume to moles of both HCl and Na2CO3.

Volume x Concentration/molarity = moles

0.235L x 0.6 M = 0.141 moles / molar ratio of 2 = 0.0705 moles of HCl

0.094L x 0.75 M = 0.0705 moles /molar ratio of 1  = 0.0705 moles of Na2CO3

Since both of the moles are equal, it means the entire reaction is complete (while the identification of limiting reactant may seem like an unnecessary step, it's quite essential in stoichiometry, so keep an eye out) and there is no excess of any reactant.

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Now we apply the C1V1 = C2V2 equation using the concentration and volume of Na2CO3 because it's molar ratio is one to one to NaCl (You can also use HCL, but you have to divide their moles by 2 for the molar ratio)  and the volume we just calculated for NaCl.

(0.75M) x (0.094L) = C2 x (0.329L)

Rearrange equation to solve for C2:

<u>(0.75M) x (0.094L)</u>  =  C2

    (0.329L)

C2 = 0.214 M (Rounded)

<u>When the reaction is finished, the NaCl solution will have a molarity concentration of 0.214 M.</u>

<u></u>

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7 0
2 years ago
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Zigmanuir [339]

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Explanation:

C6H12O6(s) + 6O2(g) ⇌6CO2(g) + 6H2O(g)

We are told that the forward reaction is exothermic, meaning heat is removed from the reacting substance to the surroundings.

According to Le Chatelier's principle,

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6 0
3 years ago
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makvit [3.9K]
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