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sdas [7]
3 years ago
5

Consider the following reactions. (Note: (s) = solid, (l) = liquid, and (g) = gas.) ½H2(g) + ½I2(g) → HI(g), ΔH = +6.2 kcal/mole

21.0 kcal/mole + C(s) + 2S(s) → CS2(l) What type of reaction is represented by the previous two examples?
Chemistry
2 answers:
Vika [28.1K]3 years ago
7 0

Answer:

Endothermic reaction.

Explanation:

Endothermic reaction is which requires or absorb energy

Exothermic reaction is which release energy.

In endothermic reaction the energy of products is more than the energy of reactants so the enthalpy of reaction is positive.

½H2(g) + ½I2(g) → HI(g), ΔH = +6.2

Thus the above reaction is endothermic

As energy is absorbed in endothermic reaction so we write the energy on reactant side.

hence the second reaction is also endothermic reaction.

BARSIC [14]3 years ago
4 0
½H2(g) + ½I2(g) → HI(g) ΔH = +6.2 kcal/mol
or...
½H2(g) + ½I2(g) + 6,2kcal/mole → HI(g)
________
21.0 kcal/mole + C(s) + 2S(s) → CS2(l)
or...
C(s) + 2S(s) → CS2(l) ΔH = +2,1 kcal/mole
_________
ΔH > 0 ----------->>> ENDOTHERMIC REACTIONS
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55\%=\frac{6.166 mol}{\text{Total moles}}\times 100

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(1 cm^3= 0.001 L)

The required volume of hexane is 0.66245 Liters.

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