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sdas [7]
3 years ago
5

Consider the following reactions. (Note: (s) = solid, (l) = liquid, and (g) = gas.) ½H2(g) + ½I2(g) → HI(g), ΔH = +6.2 kcal/mole

21.0 kcal/mole + C(s) + 2S(s) → CS2(l) What type of reaction is represented by the previous two examples?
Chemistry
2 answers:
Vika [28.1K]3 years ago
7 0

Answer:

Endothermic reaction.

Explanation:

Endothermic reaction is which requires or absorb energy

Exothermic reaction is which release energy.

In endothermic reaction the energy of products is more than the energy of reactants so the enthalpy of reaction is positive.

½H2(g) + ½I2(g) → HI(g), ΔH = +6.2

Thus the above reaction is endothermic

As energy is absorbed in endothermic reaction so we write the energy on reactant side.

hence the second reaction is also endothermic reaction.

BARSIC [14]3 years ago
4 0
½H2(g) + ½I2(g) → HI(g) ΔH = +6.2 kcal/mol
or...
½H2(g) + ½I2(g) + 6,2kcal/mole → HI(g)
________
21.0 kcal/mole + C(s) + 2S(s) → CS2(l)
or...
C(s) + 2S(s) → CS2(l) ΔH = +2,1 kcal/mole
_________
ΔH > 0 ----------->>> ENDOTHERMIC REACTIONS
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explanation.

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The circulatory system
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PLZ HELP IM CONFUSED
Marina CMI [18]

Answer:

9.1 mol

Explanation:

The balanced chemical equation of the reaction is:

CO (g) + 2H2 (g) → CH3OH (l)

According to the above balanced equation, 2 moles of hydrogen gas (H2) are needed to produce 1 mole of methanol (CH3OH).

To convert 36.7 g of hydrogen gas to moles, we use the formula;

mole = mass/molar mass

Molar mass of H2 = 2.02g/mol

mole = 36.7/2.02

mole = 18.17mol

This means that if;

2 moles of H2 reacts to produce 1 mole of CH3OH

18.17mol of H2 will react to produce;

18.17 × 1 / 2

= 18.17/2

= 9.085

Approximately to 1 d.p = 9.1 mol of methanol (CH3OH).

6 0
3 years ago
6. Cuando se oxidan en el aire 12,120 g de vapor de Zinc se obtienen 15,084 g del óxido. ¿Cuál es la fórmula empírica del óxido?
Eddi Din [679]

Answer:

 12120 g  +    O2        =    15084 g

m Zn = 12.120 Kg

m óxido = 15.084 Kg

1. calcular la masa de cinc en gramos

g = 12,120 Kg x 1000 = 12120 g de cinc

g = 15.084 Kg x 100 = 15084 g de oxígeno

2.  calcular gramos de Oxigeno

g O = 15084 g - 12120 g = 2964 g O2

3. calcular % de Zn y O

%m/m ( m soluto / m solc.) x 100

%m/m (Zn) =  ( 1210 g / 15084 g ) x 100

% m/m (Zn) = 80.35 % = 80.35 g

%m/m (O) =  ( 2964 g / 15084 g ) x 100

% m/m (Zn) = 19.65 %  = 19.65 g

4. Calcular moles de cada elemento

Zn: 80.35 g / 65.38 g/mol = 1.228 mol

O: 19.65 g / 16 g/mol = 1.228 mol

5. dividir entre el menor de los elementos

Zn: 1.228 mol / 1.228 mol = 1

O: 1.228 mol / 1.228 mol = 1

6. Fórmula empírica: ZnO

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3 years ago
Balance the equation for the reaction in which sodium oxide reacts with water to form sodium hydroxide.
tensa zangetsu [6.8K]

Answer:

➢ \: Balance \:  the  \: equation \:  for \:  the  \: reaction \\  in \:  which \:  sodium  \: oxide \:  reacts  \\ with  \: water \:  to \:  form  \: sodium \:  hydroxide.

⇒ We have Na2O + H2O --> NaOH. We have 2 sodiums and 2 oxygens and 2 hydrogens on the left side, but only one of each on the right side.

Sodium Oxide + Water → Sodium Hydroxide

⇒ Na2O + H2O → 2NaOH .

Sodium oxide is used in ceramics and glasses. Sodium oxide reacts exothermically with cold water to produce sodium hydroxide solution.

6 0
2 years ago
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