Answer:
The distance between their eye and the ceiling is 33.06 m.
Explanation:
Given that,
The ceiling of a large symphony hall is covered with acoustic tiles which have small holes that are 4.35 mm center to center, D = 4.35 mm
Diameter of the eye of pupil, d = 5.1 mm
Wavelength, 
We need to find the distance between their eye and the ceiling. Using Rayleigh criteria, we get the distance as follows :
So, the distance between their eye and the ceiling is 33.06 m.
<span>The correct answer is option B. i.e UV Rays. The Ultra violet light is the part of electromagnetic light whose wavelength is less than the Visible light light. i.e. UV range is from 10 nm to 400 nm. UV light is invisible to the naked eye.</span>
Mass always stays the same therefore it can’t be c and d. Volume stays the same because she is not removing anything. Therefore it is a
The answer is A. Mass is constant, height and width won’t change. So that leaves weight.
