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2 years ago

3. What do we call the ONLY part of the electromagnetic spectrum that we can

Physics

1 answer:

otez555 [7]2 years ago

6 0

Answer:

Visible Light

wavelength = 4000 - 7000 Angstroms = 400 - 700 milli-microns

1 A unit = 10^-10 m

1 mμ = 10^-9 m

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Un avión tarda en llegar a su destino 12 horas. Si recorrió una distancia de 10.700 kilómetros. Calcular su velocidad y expesarl

elixir [45]

Given that,

Distance, d = 10700 km

Time taken by the airplane to complete the destination, t = 12 hours

We need to find the speed of the airplane. It is equal to the total distance covered divided by total time taken. So,

$v=\dfrac{d}{t}\\\\v=\dfrac{10700\ km}{12\ h}\\\\v=891.66\ km/h$

We know that,

1 km = 1000 m

1 h = 3600 s

So,

$v=891.66\ km/h =\dfrac{891.66\times 1000\ m}{3600\ s}\\\\v=247.68\ m/s$

So, the speed of the airplane is 891.66 km/h or 247.68 m/s.

5 0

3 years ago

5kg of copper ball and I kg of water are at the same temperature of 31 C. Which

blagie [28]

Answer:

Explanation:

8 0

3 years ago

The greater the of an object the more force is needed to cause acceleration

d1i1m1o1n [39]

the greater the <u>mass</u> of an object the more force is needed to cause acceleration

8 0

4 years ago

A light-year measures the _______ that light travels in 1 year.

o-na [289]

<span>A light-year measures the distance that light travels in 1 year.

Answer : B ) Distance

-Hope this helps.</span>

4 0

3 years ago

Read 2 more answers

You have a battery marked " 6.00 V 6.00 V ." When you draw a current of 0.383 A 0.383 A from it, the potential difference betwee

Archy [21]

Answer:

V = 4.81 V

Explanation:

As the potential difference between the battery terminals, is less than the rated value of the battery, this means that there is some loss in the internal resistance of the battery.
We can calculate this loss, applying Ohm's law to the internal resistance, as follows:

$V_{rint} = I* r_{int}$

The value of the potential difference between the terminals of the battery, is just the voltage of the battery, minus the loss in the internal resistance, as follows:

$V = V_{b} - V_{rint} = 5.03 V = 6.0 V - 0.383 A* r_{int}$

We can solve for rint, as follows:

$r_{int} = \frac{V_{b}-V}{I} =\frac{6.0V-5.03V}{0.383A} = 2.53 \Omega$

When the circuit draws from battery a current I of 0.469A, we can find the potential difference between the terminals of the battery, as follows:

$V = V_{b} - V_{rint} = 6.0 V - 0.469 A* 2.53 \Omega= 6.0 V - 1.19 V = 4.81 V$

As the current draw is larger, the loss in the internal resistance will be larger too, so the potential difference between the terminals of the battery will be lower.

5 0

3 years ago