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inna [77]
3 years ago
13

Does the following scenario describe a dependent or independent sequence of events: Flipping a coin and getting a "heads" and th

en flipping a second coin and getting a "heads".
Mathematics
1 answer:
Vladimir [108]3 years ago
3 0

Answer:

I hope this helps <3

Step-by-step explanation:

What's the probability of getting heads on the second toss given that the first toss was a head. (Trying to refresh my probability a bit). I've seen this analyzed like this:

HH 1/4

HT 1/4

TH 1/4

TT 1/4

So since we are given information (Head on first flip), then TT goes away and were are left with:

HH 1/3

HT 1/3

TH 1/3

So we could say that HH now has a 1/3 probability. Should we not also get rid of TH, since we know that the first flip is a head? So now we have:

HH 1/2

HT 1/2

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You have $12,000 to invest and want to keep your money invested for 8 years. You are considering the following investment option
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Mary took out a student loan for $15000 at 4% simple interest. How much interest will she pay in 10 years? suppose she paid it o
sergey [27]

Simple interest formula:

Total = principal x (1 + rate x years)

10 years:

Total = 15,000(1+0.04x10)

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PLEASE HELP? SERIOUSLY? :)
IRINA_888 [86]
2x + 5y = -8 . . . (1)
-133x - 4y = -8 . . . (2)

(1) * 4 => 8x + 20y = -32 . . . (3)
(2) * -5 => -665x + 20y = 32 . . . (4)

(3) - (4) => 673x = 0
x = 0
From (1), 2(0) + 5y = -8
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3 0
3 years ago
PLEASE ANSWER FAST:
Butoxors [25]

Answer:

(2,7)

Step-by-step explanation:

Variable Definitions:

​

x=

x=

\,\,\text{the number of apples}

the number of apples

y=

y=

\,\,\text{the number of bananas}

the number of bananas

\text{\textquotedblleft a minimum of 7 items"}\rightarrow \text{7 or more items}

“a minimum of 7 items"→7 or more items

Use a \ge≥ symbol

Therefore the total number of apples and bananas, x+yx+y, must be greater than or equal to 7:7:

x+y\ge 7

x+y≥7

\text{\textquotedblleft \$8 to spend"}\rightarrow \text{can spend \$8 or less}

“$8 to spend"→can spend $8 or less

Use a \le≤ symbol

One apple costs $2, so xx apples cost 2x.2x. One banana costs $0.50, so yy bananas cost 0.50y.0.50y. The total 2x+0.50y2x+0.50y must be less than or equal to \$8:$8:

2x+0.50y\le 8

2x+0.50y≤8

\text{Solve each inequality for }y\text{:}

Solve each inequality for y:

\begin{aligned}x+y\ge 7\hspace{30px}& 2x+0.50y\le 8 \\[0.8em] y\ge 7-x \hspace{30px}& 0.50y\le 8-2x \\[0.8em] \hspace{30px}& y\le \frac{8-2x}{0.50} \\[0.8em] & y\le 16-4x\end{aligned}

x+y≥7

y≥7−x

​

 

2x+0.50y≤8

0.50y≤8−2x

y≤

0.50

8−2x

​

y≤16−4x

​

Graph y\ge 7-xy≥7−x by shading up and graph y\le 16-4xy≤16−4x by shading down:

0

the number of apples

the number of bananas

x

y

0

the number of apples

the number of bananas

(2, 7)

Since the point (2, 7(2,7) is inside the double shaded region, one possible solution to the system of inequalities would be:

Zoey could buy 2 apples and 7 bananas.

3 0
3 years ago
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