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3 years ago

11

Find the inverse function 5/2x-15

1 answer:

Yuliya22 [10]3 years ago

6 0

F^-1(x)=6+2x/5 is ur inverse

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Match the numerical expressions to their simplified forms

eduard

Answer:

$1.\ \ p^2q = (\frac{p^5}{p^{-3}q^{-4}})^{\frac{1}{4}}$

$2.\ \ pq^{\frac{3}{2}}} = (\frac{p^2q^7}{q^{4}})^{\frac{1}{2}}$

$3.\ \ pq^2 = \frac{(pq^3)^{\frac{1}{2}}}{(pq)^{\frac{-1}{2}}}$

$4.\ \ p^2q^{\frac{1}{2}} = (p^6q^{\frac{3}{2}})^{\frac{1}{3}}$

Step-by-step explanation:

Required

Match each expression to their simplified form

1.

$(\frac{p^5}{p^{-3}q^{-4}})^{\frac{1}{4}}$

Simplify the expression in bracket by using the following law of indices;

$\frac{a^m}{a^n} = a^{m-n}$

The expression becomes

$(\frac{p^{5-(-3)}}{q^{-4}})^{\frac{1}{4}}$

$(\frac{p^{5+3}}{q^{-4}})^{\frac{1}{4}}$

$(\frac{p^8}{q^{-4}})^{\frac{1}{4}}$

Split the fraction in the bracket

$(p^8*\frac{1}{q^{-4}})^{\frac{1}{4}}$

Simplify the fraction by using the following law of indices;

$\frac{1}{a^{-m}} = a^m$

The expression becomes

$(p^8*q^4)^{\frac{1}{4}}$

Further simplify the expression in bracket by using the following law of indices;

$(ab)^m = a^m * b^m$

The expression becomes

$(p^{8*\frac{1}{4}}\ *\ q^4*^{\frac{1}{4}})$

$(p^{\frac{8}{4}}\ *\ q^{\frac{4}{4}})$

$p^2q$

Hence,

$(\frac{p^5}{p^{-3}q^{-4}})^{\frac{1}{4}} = p^2q$

2.

$(\frac{p^2q^7}{q^{4}})^{\frac{1}{2}}$

Simplify the expression in bracket by using the following law of indices;

$\frac{a^m}{a^n} = a^{m-n}$

The expression becomes

$({p^2q^{7-4}}})^{\frac{1}{2}}$

$({p^2q^3}})^{\frac{1}{2}}$

Further simplify the expression in bracket by using the following law of indices;

$(ab)^m = a^m * b^m$

The expression becomes

${p^{2*\frac{1}{2}}q^{3*\frac{1}{2}}}}$

$pq^{\frac{3}{2}}}$

Hence,

$pq^{\frac{3}{2}}} = (\frac{p^2q^7}{q^{4}})^{\frac{1}{2}}$

3.

$\frac{(pq^3)^{\frac{1}{2}}}{(pq)^{\frac{-1}{2}}}$

Simplify the numerator as thus:

$\frac{p^{\frac{1}{2}} * q^3*^{\frac{1}{2}}}{(pq)^{\frac{-1}{2}}}$

$\frac{p^{\frac{1}{2}} * q^{\frac{3}{2}}}{(pq)^{\frac{-1}{2}}}$

Simplify the denominator as thus:

$\frac{p^{\frac{1}{2}} * q^{\frac{3}{2}}}{p^{\frac{-1}{2}}q^{\frac{-1}{2}}}$

Simplify the expression in bracket by using the following law of indices;

$\frac{a^m}{a^n} = a^{m-n}$

The expression becomes

$p^{\frac{1}{2} - (\frac{-1}{2} )} * q^{\frac{3}{2} - (\frac{-1}{2}) }$

$p^{\frac{1}{2} +\frac{1}{2} } * q^{\frac{3}{2} + \frac{1}{2} }$

$p^{\frac{1+1}{2}} * q^{\frac{3+1}{2}}$

$p^{\frac{2}{2}} * q^{\frac{4}{2}}$

$pq^2$

Hence,

$pq^2 = \frac{(pq^3)^{\frac{1}{2}}}{(pq)^{\frac{-1}{2}}}$

4.

$(p^6q^{\frac{3}{2}})^{\frac{1}{3}}$

Simplify the expression in bracket by using the following law of indices;

$(ab)^m = a^m * b^m$

The expression becomes

$p^6*^{\frac{1}{3}}\ *\ q^{\frac{3}{2}}*^{\frac{1}{3}}$

$p^{\frac{6}{3}}\ *\ q^{\frac{3*1}{2*3}}$

$p^2 *\ q^{\frac{3}{6}}$

$p^2 *\ q^{\frac{1}{2}$

$p^2q^{\frac{1}{2}$

Hence

$p^2q^{\frac{1}{2}} = (p^6q^{\frac{3}{2}})^{\frac{1}{3}}$

6 0

3 years ago

Cole walked 2 1/2 kilometers on Monday. Isabella walked twice as many kilometers as coke. How many meters did cole and Isabella

QveST [7]

Answer:

7500 meters

Step-by-step explanation:

Isabella walked 2 × 2.5 km = 5 km. Together, they walked ...

2.5 km + 5 km = 7.5 km = 7.5×1000 m = 7500 m

Cole and Isabella walked 7500 meters altogether.

_____

"kilo-" is a prefix meaning "one thousand". So one kilometer is 1000 meters. Then 7.5 kilometers is 7.5 times 1000 meters, or 7500 meters.

8 0

4 years ago

I’ll give a brainlist questions in the attachments

FinnZ [79.3K]

Answer:

38.1

Step-by-step explanation:

36.5 + 37.7 + 38.2 + 38.4 +38.9 + 39.1 = 228.8

228.8 ÷ 6 = 38.1

5 0

3 years ago

Smplify the expression:<br> 5+6i/4+6i

skelet666 [1.2K]

The answer would be 5 + 15i/2.

1. 5 + 3i/2 + 6i

2. 5 + (3/2i + 6i)

3. 5 + 15i/2.

5 0

3 years ago

Anthony, Brian and Chris are hired for a job. If Anthony and Brian are working together they will finish the job in minutes. If

Tcecarenko [31]

Answer:

12.5

Step-by-step explanation:

Let individual time taken by Anthony, Brian and Chris = t1 , t2 , t3 respectively

So, total time taken by A & B = 1 / t1 + 1 / t2 , lets suppose = 10 {i}

Total time taken by A & C = 1 / t1 + 1 / t3 , lets suppose = 15 {ii}

Total time taken by B & C = 1 / t2 + 1 / t3 , lets suppose = 20 {iii}

From {i} , 1 / t2 = 10 - 1 / t1

From {ii} 1 / t1 = 15 - 1 / t3

By above two eqtns , 1 / t2 = 10 - (15 - 1 / t3)

1 / t2 = 1 / t3 - 5

Putting in {iii} , 1 / t3 - 5 + 1 / t3 = 20

2 / t3 = 25

t3 = 12.5

5 0

3 years ago