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sergey [27]
2 years ago
12

Help please Find the perimeter of this quarter circle

Mathematics
1 answer:
aniked [119]2 years ago
6 0

Answer:

6.28

Step-by-step explanation:

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The measures of the angles of a triangle solve for X
kompoz [17]

Answer:

x = 7

Step-by-step explanation:

Because this is a right triangle, one angle is a right angle (90°). All triangles have all three angle measures adding up to 180°, so the other two angles' measures add up to 90° (90 + 90 = 180).

Combine like terms of the angle measures.

6x + 9x = 15x

-3 + (-12) = -15

15x - 15

Because the sum of the measures of the two angles have to equal 90,

15x - 15 = 90

Add 15 from both sides.

15x = 105

Divide both sides by 15.

x = 7

To check, substitute 7 in both expressions.

6(7) - 3 = 39

9(7) - 12 = 51

39 + 51 + 90 (the measure of the right angle) = 180, so the value of x is 7.

I hope this helped :)

7 0
3 years ago
Hello please help me quick!
Ronch [10]

Answer:

Answer is A

Step-by-step explanation:

subtract 15 1/4 and 2 2/3

4 0
3 years ago
Find the missing side length. Show all of your work. *
ratelena [41]
6²+8²=c²
36+64=c²
c²=100
c=10
7 0
3 years ago
Read 2 more answers
Simplify. 3x+8−x−6 Enter your answer in the box.
Stolb23 [73]
Answer: 52x

Explanation
6 0
3 years ago
What is the solution set of the equation using the quadratic formula?
oee [108]

(1)

we are given

x^2+6x+10=0

we can use quadratic formula

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

now, we can compare and find a , b and c

we get

a=1,b=6,c=10

now, we can plug these values into quadratic formula

x=\frac{-6\pm \sqrt{6^2-4(1)(10)}}{2(1)}

x=\frac{-6+\sqrt{6^2-4\cdot \:1\cdot \:10}}{2\cdot \:1}

we can simplify it

x=-3+i

x=\frac{-6-\sqrt{6^2-4\cdot \:1\cdot \:10}}{2\cdot \:1}

x=-3-i

so, we will get solution

{−3+i, −3−i}.........Answer

(2)

we are given equation as

x^2-8x+14=0

Since, Jamal solve this equation by completing square

so, firstly we will move constant term on right side

so,  subtract both sides by 14

x^2-8x+14-14=0-14

x^2-8x=-14

we can write

-8x=-2\times 4\times x

so, we will add both sides by 4^2

x^2-8x+4^2=-14+4^2

we get

x^2-8x+16=-14+16..............Answer


4 0
3 years ago
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