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3 years ago

Kinetic Friction force is always less than Static Friction force.

Physics

1 answer:

mars1129 [50]3 years ago

4 0

Answer:

true

Explanation:

Initially it requires more force to break the interlock between the irregularities of two surfaces. But once the block is in motion, it takes time to interlock between the irregularities of two surfaces. Also, the body gains the inertia of motion.

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No matter what values of m and k you used for the spring, what is the ratio of the period to k m.

Leto [7]

The relationship between the period of an oscillating spring and the attached mass determines the ratio of the period to $\sqrt{\dfrac{m}{k} }$ .

Response:

The ratio of the period to $\sqrt{\dfrac{m}{k} }$ is always approximately 2·π : 1

<h3>How is the value of the ratio of the period to $\sqrt{\dfrac{m}{k} }$ calculated?</h3>

Given:

The relationship between the period, T, the spring constant k, and the

mass attached to the spring m is presented as follows;

$T = \mathbf{2 \cdot \pi \cdot \sqrt{\dfrac{m}{k} }}$

Therefore, the fraction of of the period to $\sqrt{\dfrac{m}{k} }$ , is given as follows;

$\mathbf{\dfrac{T}{ \sqrt{\dfrac{m}{k} }}} = 2 \cdot \pi$

2·π ≈ 6.23

Therefore;

$T :{ \sqrt{\dfrac{m}{k} }} = 2 \cdot \pi : 1$

Which gives;

The ratio of the period to $\sqrt{\dfrac{m}{k} }$ is always approximately 2·π : 1

Learn more about the oscillations in spring here:

brainly.com/question/14510622

7 0

3 years ago

An electron moving along the x axis has an initial speed of 1 × 106 m/s at the origin. Its speed is reduced to 5 × 105 m/s at th

mina [271]

Answer:

-2.13 V

Explanation:

Given parameters are:

$v_i = 1 * 10^6$ m/s

$v_f = 5 * 10^5$ m/s

$q = -e = 1.602 * 10^{-19}$ C

$m = 9.109 * 10^{-31}$ kg

By conservation of energy principle, we know that the potential difference between two points is equal to the change in the kinetic energy between these points.

$-\Delta U = \Delta KE\\\\-e\Delta V = \frac{1}{2} mv_f^2 - \frac{1}{2} mv_i^2$

Hence,

$1.602*10^{-19}\Delta V = \frac{1}{2}*9.11*10^{-31}((5*10^5)^2 - (1*10^6)^2)$

⇒ $\Delta V = -2.13$ V

5 0

4 years ago

a pole vaulter at the top of his vault is 6.15 m in the air . if he has a gravitational potential energy of 4o42 j , what is his

Ksenya-84 [330]

82.0 kg I am going to assume that there is a typo for the number of joules of energy. Doing a google search for this exact question showed this question multiple times with a value of 4942 joules which makes sense given how close the "o" key is to the "9" key. Because of this, I will assume that the correct value for the number of joules is 4942. With that in mind, here's the solution. The gravitational potential energy is expressed as the mass multiplied by the height, multiplied by the local gravitational acceleration. So: E = MHA Solving for M, the substituting the known values and calculating gives: E = MHA E/(HA) = M 4942/(6.15*9.8) = M 4942/60.27 = M 81.99767712 = M Rounding to 3 significant figures gives 82.0 kg

4 0

4 years ago

Read 2 more answers

What determines an object’s velocity?

joja [24]

Answer:

I think it's 3) speed and direction

8 0

4 years ago

A person walks 12 meters to the west and then 16 meters back to the east. what is the distance covered and the direction of disp

devlian [24]

The distance is 28 meters and the direction of displacement is East I think

6 0

3 years ago