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nikitadnepr [17]

3 years ago

15

What determines an object’s velocity?

1 answer:

joja [24]3 years ago

8 0

Answer:

I think it's 3) speed and direction

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A person with a remote mountain cabin plans to install her own hydroelectric plant. A nearby stream is 3.00 m wide and 0.500 m d

Lubov Fominskaja [6]

Answer:

The power she can generate is 185.22 KW.

Explanation:

<h3><u>DATA</u></h3>

3.00m wide and 0.500m deep.

Cross sectional area = 1.500m^2

Velocity = 1.35m/s

Volumetric flow rate = Av = 18.00m^3/s

Mass flow rate = 18,000kg/s

Height = 4.20m

25.0% efficiency

<h3><u> FORMULA:</u></h3>

P = dE / dt * eff

<h3><u>SOLUTION:</u></h3>

18,000kg/s (9.8m/s^2) (4.20m) (25%) = 185,220 watts

= 185 kw

6 0

3 years ago

A large mass collides with a stationary, smaller mass. How will the masses behave if the collision is inelastic?

iragen [17]

Logically both masses will collide and well make a reaction. first of all depending on the small mass it will either merge or unite with the big mass or it will bounce away from it . if this happen it will make a reaction that will affect both masses. Hope this helps if it is incorrect please let me know :)

3 0

3 years ago

A 3-m-high, 7-m-wide rectangular gate is hinged at the top edge and is restrained by a fixed ridge. Determine the hydrostatic fo

Shalnov [3]

Answer:

The Hydrostatic force is $F = 137.2 kN$

The location of pressure center is $Z = 1.333 \ m$

Explanation:

From the question we are told that

The height of the gate is $h = 3 \ m$

The weight of the gate is $w = 7 \ m$

The height of the water is $h_w = 2 \ m$

The density of water is $\rho_w = 1000 \ kg/m^3$

Note used $h_w$ for height of water and height of gate immersed by water since both have the same value

The area of the gate immersed in water is mathematically represented as

$A = h_w * w$

substituting values

$A = 2* 7$

$A = 14 \ m^2$

The hydrostatic force is mathematically represented as

$F = \rho_w * g * h_f * A$

Where

$h_f =h- h_w$

$h_f =3 -2$

$h_f = 1\ m$

So

$F = 1000 * 9.8 * 1 * 14$

$F = 137.2 kN$

The center of pressure is mathematically represented as

$Z = h_f + \frac{I_g}{h_f * A}$

Where $I_g$ is the moment of inertia of the gate which mathematically represented as

$I_g = \frac{w * h_w^2}{12}$

The $h_w$ is the height of gate immersed in water

$I_g = \frac{7 * 2^2 }{12}$

$I_g = 4.667\ kg m^2$

Thus

$Z = 1 + \frac{4.66}{1 * 14}$

$Z = 1.333 \ m$

3 0

3 years ago

Greg drew a diagram to compare two of the fundamental forces.

Mashcka [7]

Answer:

X: Always attractive

Y: Infinite range

Z: Attractive or repulsive

ANSWER IS C

8 0

3 years ago

Read 2 more answers

A 38.2 kg wagon is towed up a hill inclined at 17.5 ◦ with respect to the horizontal. The tow rope is parallel to the incline an

Tema [17]

Answer:

v = 8.57 m/s

Explanation:

As we know that the wagon is pulled up by string system

So the net force on the wagon along the inclined is due to tension in the rope and component of weight along the inclined plane

So as per work energy theorem we know that

work done by tension force + work done by force of gravity = change in kinetic energy

$F_t . d - (mgsin\theta)(d) = \frac{1}{2}mv^2 - 0$

so we have

$F_t = 129 N$

$\theta = 17.5^o$

m = 38.2 kg

d = 85.4 m

so now we have

$129(85.4) - (38.2)9.8sin17.5 (85.4) = \frac{1}{2}(38.2) v^2$

$v = 8.57 m/s$

7 0

3 years ago