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3 years ago

Name two types of mechanical weathering in NewBedford

Physics

1 answer:

mario62 [17]3 years ago

8 0

Answer:

Explanation:

Mechanical weathering types

Mechanical weathering is the breaking down of rocks into smaller pieces without changing the composition of the minerals in the rock. This can be divided into four basic types – abrasion, pressure release, thermal expansion and contraction, and crystal growth.

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You drop a 30 g pebble down a well. You hear a splash 2.7 s later. Ignoring air resistance, how deep is the well? Assume g = 9.8

lys-0071 [83]

I will assume here that the well is sufficiently short so that the time the sound takes to come from the bottom of the well to our ear is negligible.

Since the pebble moves by uniformly accelerated motion, the distance it covers is given by
$S= \frac{1}{2}gt^2$
where
$g=9.81 m/s^2$ is the gravitational acceleration
$t=2.7 s$ is the time the pebble takes to reach the bottom of the well

Therefore, the depth of the well is
$S= \frac{1}{2}(9.81 m/s^2)(2.7 s)^2 = 35.7 m \sim 36 m$
and the correct answer is B.

8 0

3 years ago

What is the net force on the object represented by the FBD below?

ololo11 [35]

Explanation:

hope you understood fella

5 0

3 years ago

Si olvidas un trozo de chocolate cerca de la estufa encendida, al rato, observa tu chocolate derretido, ¿Cómo estarán las partíc

eduard

Answer:

partículas estarían separadas

Explanation:

ya que con el calor las partículas se alborotan y con frío se congelan

4 0

3 years ago

Calculate the propellant mass required to launch a 2000 kg spacecraft from a 180 km circular orbit on a Hohmann transfer traject

Finger [1]

Answer:

t = 12,105.96 sec

Explanation:

Given data:

weight of spacecraft is 2000 kg

circular orbit distance to saturn = 180 km

specific impulse = 300 sec

saturn orbit around the sun R_2 = 1.43 *10^9 km

earth orbit around the sun R_1= 149.6 * 10^ 6 km

time required for the mission is given as t

$t = \frac{2\pi}{\sqrt{\mu_sun}} [\frac{1}{2}(R_1 + R_2)]^{3/2}$

where

$\mu_{sun}$ is gravitational parameter of sun = 1.32712 x 10^20 m^3 s^2. $t = \frac{2\pi}{\sqrt{ 1.32712 x 10^{20}}} [\frac{1}{2}(149.6 * 10^ 6 +1.43 *10^9 )]^{3/2}$

t = 12,105.96 sec

6 0

3 years ago

a 4050 N sled is being pushed with a force of 575 N. If it encounters a frictional force of 385 N… determine the net force

creativ13 [48]

According to the solving the net force is:

= 3,860.

<h3>Why is net force important?</h3>

The net force is the total of all the forces operating on an object, according to its definition. Mass can be accelerated by net force. Whether a body is at rest or in motion, another force is at work on it. When a system has a lot of forces acting on it, the phrase "net force" is employed.

<h3>What's the net force equation?</h3>

When a body is moving and multiple forces, such as the normal force, frictional force, and gravitational force, are acting on it, the combined effect is known as net force. As a result, is the net force formula. FNet equals Fa, Fg, Ff, and FN.

<h3>According to the given data:</h3>

4050 N sled

force of 575 N.

encounters a frictional force of 385 N

So the net force will be:

(Net)F = F₁ + F₂ + F₃

So,

(Net)F = F₁ + F₂ - F₃(frictional force)

(Net)F = 4050 + 385 - 575

= 3,860

According to the solving the net force is:

= 3,860.

To know more about net force visit:

brainly.com/question/18109210

#SPJ10

8 0

1 year ago