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Artyom0805 [142]
3 years ago
6

a pole vaulter at the top of his vault is 6.15 m in the air . if he has a gravitational potential energy of 4o42 j , what is his

mass?
Physics
2 answers:
Ksenya-84 [330]3 years ago
4 0
<span>82.0 kg I am going to assume that there is a typo for the number of joules of energy. Doing a google search for this exact question showed this question multiple times with a value of 4942 joules which makes sense given how close the "o" key is to the "9" key. Because of this, I will assume that the correct value for the number of joules is 4942. With that in mind, here's the solution. The gravitational potential energy is expressed as the mass multiplied by the height, multiplied by the local gravitational acceleration. So: E = MHA Solving for M, the substituting the known values and calculating gives: E = MHA E/(HA) = M 4942/(6.15*9.8) = M 4942/60.27 = M 81.99767712 = M Rounding to 3 significant figures gives 82.0 kg</span>
Rufina [12.5K]3 years ago
3 0

Gravitational potential energy is given by 

 U=mgh

 where 

 m is the mass of the object 

 h is the height of the object above the ground (Earth's surface)

 g is the gravitational acceleration constant, 9.8ms2.

 For h=6.15m and U=4042J, we can rearrange to solve for m:

 m=U/gh

 m=(4042J)/((9.8m/s^2)*(6.15m))

 m=67.06 Kg

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Trigonometry allows finding the result for the decomposition of the displacement vector is:  

           x = 2.12 mi

           y = -2.12 mi

Displacement is a vector quantity, which has modulus and direction.

The cardinal points are a reference system with respect to which measurements are made, this system is related to the Cartesian system with the East in the positive direction of the x-axis and the North with the positive direction of the y-axis.

In the attached we can see a diagram of the vector and its components, the indicated direction of 45 S of the E, in the Cartesian system where the angles are measured from the positive side of the x-axis in a counterclockwise direction is:

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             θ = 315º  

Let's use trigonometry to decompose the vector d = 3 mi  

              cos 315 = \frac{x}{d}  

              sin 315 =  \frac{y}{d}  

               

              x = d cos 315

              y = d sin 315

Let's calculate

              x = 3 cos 315

              y = 3 sin 315

              x = 2.12 mi

              y = -2.12 mi

The negative sign indicates that the displacement is towards the negative side, that is, towards the South.

In conclusion using trigonometry we can find the result for the decomposition of the displacement vector are:  

           x = 2.12 mi

           y = -2.12 mi

Learn more here:  brainly.com/question/1666179

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