A
f(x) = 2x + 1
f(3) = 2*3 + 1 = 7
B
g(x) = x^2
g(7) = 7^2
g(7)= 49
C
f(g(x)) = 2(g(x) + 1
f(g(x)) = 2 x^2 + 1
f(g(3) = 2* 3^2 + 1
f(g(3) = 19
D
g(f(x)) = (f(x))^2
g(f(x)) = (2x + 1)^2
g(f(3)) = (2*3 + 1)^2 = (6 + 1)^2 = 49
E
f(g(x)) = 2*g(x) + 1
f(g(x)) = 2*x^2 + 1
f(g(3)) = 2*3^2 + 1
f(g(3)) = 2 * 9 + 1
f(g(3)) = 18 + 1
f(g(3) = 19
F
f(g(x)) = 2(g(x)) + 1
f(g(x)) = 2*x^2 + 1
Answer:
3(2)+8= 14
Step-by-step explanation:
Answer:
sqrt39
Step-by-step explanation:
Because AE is 5 because the square intersects by half based on the SSS theorem. Therefore we can use The Pythagorean Theorem and get 8^2-5^2 to get sqrt39
Answer:
B
Step-by-step explanation:
× 
( no factors cancel on numerator / denominator )
= 
= 
