*see attachment for diagram
Answer:
Perimeter = 38
Step-by-step explanation:
Recall: when two tangents are drawn to meet at a point outside a circle, the segments of the two tangents are congruent.
Given,
CQ = 5
PQ = 10
PR = 14
Perimeter of ∆PQR = RC + CQ + QB + BP + PA + AR
CQ = QB = 5 (tangents drawn from an external point)
BP = PQ - QB
BP = 10 - 5 = 5
BP = PA = 5 (tangents drawn from an external point)
AR = PR - PA
AR = 14 - 5 = 9
AR = RC = 9 (tangents drawn from an external point)
✔️Perimeter of ∆PQR = RC + CQ + QB + BP + PA + AR
= 9 + 5 + 5 + 5 + 5 + 9
Perimeter = 38
Answer:
y = -4x+15
Step-by-step explanation:
y=x/4+5 may be presented as y = 1/4 x + 5, where a=1/4, b=5
swapping numerator and denominator and inserting an opposite sign in a=1/4, we have:
1/4 --------> 4/1 -------> -4/1 = -4
y = -4x+n
Point (2,7) means that x=2, y=7 substitute it to the equation y=-4x+n, calculate "n":
7=-4*2+n ------> 7=-8+n -------> 7+8 = n -------> 15=n
substituting n=15 to the equation y=-4x+n, we get finally y=-4x+15
Answer: Note that the ADS and GDS recovery period for cars, light trucks, an computers are the same, 5 years.
Step-by-step explanation:
I believe it would be 12/18 so that would be 2/3 and 0.6 in decimal form
