Answer:
Step-by-step explanation:
Let the first number = x
Let the second number = x + 9
Let the third number = 4x
Together they make 123
x + x + 9 + 4x = 123 combine the left
6x + 9 = 123 Subtract 9 from both sides
6x = 123 - 9
6x = 114 Divide by 6
x = 114/6
x = 19
=================
First number = 19
Second number = 19 + 9 = 28
Third number = 4*19 = 76
<span>The number 6 – 8i is located in the 4th quadrant </span><span>on the complex plane.</span>
Answer: The TV is 48 inches wide.
Step-by-step explanation: To find the solution to this equation we must use the Pythagorean theorem. The Py. Theo. is basically the formula :
a^2 + b^2 = c^2 You say this as "A squared plus b squared equals c squared"
To use this formula you must plug in the given values of a and b, to find c. A and b represent the two bases of the triangle, while c is the hypotenuse. In this equation we already have the value of c and a. We need to find b, but in order to do that we use a different formula. We use : c^2 - a^2 = b^2
See :
52^2 - 20^2 = b^2 *The ^2 means "to the power of" aka an exponent*
2704 - 400 = b^2 *When dealing with ^2, all you do is multiply the number by itself*
2304 = b^2 *Next, we find the square root of our current number.*
48 = b
*Another way to solve this equation is to memorize all the Pythagorean Triples. With that knowledge, you wont even need to use the formula because you will already know all three values. I hope this helped you understand :)
![\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad \sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\ -------------------------------\\\\ (4x^5\cdot x^{\frac{1}{3}})+(2x^4\cdot x^{\frac{1}{3}})-(7x^3\cdot x^{\frac{1}{3}})+(3x^2\cdot x^{\frac{1}{3}})\\\\+(9x^1\cdot x^{\frac{1}{3}})-(1\cdot x^{\frac{1}{3}}) \\\\\\ 4x^{5+\frac{1}{3}}+2x^{4+\frac{1}{3}}-7x^{3+\frac{1}{3}}+9x^{1+\frac{1}{3}}-x^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Cbf%20a%5E%7B%5Cfrac%7B%7B%20n%7D%7D%7B%7B%20m%7D%7D%7D%20%5Cimplies%20%20%5Csqrt%5B%7B%20m%7D%5D%7Ba%5E%7B%20n%7D%7D%20%5Cqquad%20%5Cqquad%0A%5Csqrt%5B%7B%20m%7D%5D%7Ba%5E%7B%20n%7D%7D%5Cimplies%20a%5E%7B%5Cfrac%7B%7B%20n%7D%7D%7B%7B%20m%7D%7D%7D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0A%284x%5E5%5Ccdot%20x%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%29%2B%282x%5E4%5Ccdot%20x%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%29-%287x%5E3%5Ccdot%20x%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%29%2B%283x%5E2%5Ccdot%20x%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%29%5C%5C%5C%5C%2B%289x%5E1%5Ccdot%20x%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%29-%281%5Ccdot%20x%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%29%0A%5C%5C%5C%5C%5C%5C%0A4x%5E%7B5%2B%5Cfrac%7B1%7D%7B3%7D%7D%2B2x%5E%7B4%2B%5Cfrac%7B1%7D%7B3%7D%7D-7x%5E%7B3%2B%5Cfrac%7B1%7D%7B3%7D%7D%2B9x%5E%7B1%2B%5Cfrac%7B1%7D%7B3%7D%7D-x%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\bf 4x^{\frac{16}{3}}+2x^{\frac{13}{3}}-7x^{\frac{10}{3}}+9x^{\frac{4}{3}}-x^{\frac{1}{3}} \\\\\\ 4\sqrt[3]{x^{16}}+2\sqrt[3]{x^{13}}-7\sqrt[3]{x^{10}}+9\sqrt[3]{x^4}-\sqrt[3]{x}](https://tex.z-dn.net/?f=%5Cbf%204x%5E%7B%5Cfrac%7B16%7D%7B3%7D%7D%2B2x%5E%7B%5Cfrac%7B13%7D%7B3%7D%7D-7x%5E%7B%5Cfrac%7B10%7D%7B3%7D%7D%2B9x%5E%7B%5Cfrac%7B4%7D%7B3%7D%7D-x%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%0A%5C%5C%5C%5C%5C%5C%0A4%5Csqrt%5B3%5D%7Bx%5E%7B16%7D%7D%2B2%5Csqrt%5B3%5D%7Bx%5E%7B13%7D%7D-7%5Csqrt%5B3%5D%7Bx%5E%7B10%7D%7D%2B9%5Csqrt%5B3%5D%7Bx%5E4%7D-%5Csqrt%5B3%5D%7Bx%7D)
![\bf 4x^{5-\frac{1}{3}}+2x^{4-\frac{1}{3}}-7x^{3-\frac{1}{3}}+9x^{1-\frac{1}{3}}-x^{-\frac{1}{3}} \\\\\\ 4x^{\frac{14}{3}}+2x^{\frac{11}{3}}-7x^{\frac{8}{3}}+9x^{\frac{2}{3}}-x^{-\frac{1}{3}} \\\\\\ 4\sqrt[3]{x^{14}}+2\sqrt[3]{x^{11}}-7\sqrt[3]{x^{8}}+9\sqrt[3]{x^{2}}-\frac{1}{\sqrt[3]{x}}](https://tex.z-dn.net/?f=%5Cbf%204x%5E%7B5-%5Cfrac%7B1%7D%7B3%7D%7D%2B2x%5E%7B4-%5Cfrac%7B1%7D%7B3%7D%7D-7x%5E%7B3-%5Cfrac%7B1%7D%7B3%7D%7D%2B9x%5E%7B1-%5Cfrac%7B1%7D%7B3%7D%7D-x%5E%7B-%5Cfrac%7B1%7D%7B3%7D%7D%0A%5C%5C%5C%5C%5C%5C%0A4x%5E%7B%5Cfrac%7B14%7D%7B3%7D%7D%2B2x%5E%7B%5Cfrac%7B11%7D%7B3%7D%7D-7x%5E%7B%5Cfrac%7B8%7D%7B3%7D%7D%2B9x%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D-x%5E%7B-%5Cfrac%7B1%7D%7B3%7D%7D%0A%5C%5C%5C%5C%5C%5C%0A4%5Csqrt%5B3%5D%7Bx%5E%7B14%7D%7D%2B2%5Csqrt%5B3%5D%7Bx%5E%7B11%7D%7D-7%5Csqrt%5B3%5D%7Bx%5E%7B8%7D%7D%2B9%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%7D-%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7Bx%7D%7D)
![\bf \begin{cases} f(x)=\sqrt{x}-5x\implies &f(x)x^{\frac{1}{2}}-5x\\\\ g(x)=5x^2-2x+\sqrt[5]{x}\implies &g(x)=5x^2-2x+x^{\frac{1}{5}} \end{cases} \\\\\\ \textit{let's multiply the terms from f(x) by each term in g(x)} \\\\\\ x^{\frac{1}{2}}(5x^2-2x+x^{\frac{1}{5}})\implies x^{\frac{1}{2}}5x^2-x^{\frac{1}{2}}2x+x^{\frac{1}{2}}x^{\frac{1}{5}}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%0Af%28x%29%3D%5Csqrt%7Bx%7D-5x%5Cimplies%20%26f%28x%29x%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D-5x%5C%5C%5C%5C%0Ag%28x%29%3D5x%5E2-2x%2B%5Csqrt%5B5%5D%7Bx%7D%5Cimplies%20%26g%28x%29%3D5x%5E2-2x%2Bx%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ctextit%7Blet%27s%20multiply%20the%20terms%20from%20f%28x%29%20by%20each%20term%20in%20g%28x%29%7D%0A%5C%5C%5C%5C%5C%5C%0Ax%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%285x%5E2-2x%2Bx%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%29%5Cimplies%20x%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D5x%5E2-x%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D2x%2Bx%5E%7B%5Cfrac%7B1%7D%7B2%7D%7Dx%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D)
![\bf 5\sqrt{x^5}-2\sqrt{x^3}+\sqrt[10]{x^7}-25x^3+10x^2-5\sqrt[5]{x^6}](https://tex.z-dn.net/?f=%5Cbf%205%5Csqrt%7Bx%5E5%7D-2%5Csqrt%7Bx%5E3%7D%2B%5Csqrt%5B10%5D%7Bx%5E7%7D-25x%5E3%2B10x%5E2-5%5Csqrt%5B5%5D%7Bx%5E6%7D)
