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castortr0y [4]
3 years ago
10

4r= -36 -72 -40 -9 9

Mathematics
2 answers:
xz_007 [3.2K]3 years ago
8 0

Answer: r=−9

Step-by-step explanation: Hope this help :D

Let's solve your equation step-by-step.

4r=−36

Step 1: Divide both sides by 4.

4r/4=−36/4r

=−9

icang [17]3 years ago
7 0

Answer:

4r=-36

-36/4=r

-9=r

Therefore

r=-9

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What is the formula for the area A of a circle in terms of the radius r?​
svet-max [94.6K]

Answer:

n * r ^2

Step-by-step explanation:

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2 years ago
What is x, the angle at which the diagonal beam meets the 10-foot beam at the top of the frame? 16.7° 17.5° 72.5° 73.3°
umka21 [38]

The complete question is

"A theater production group is making frames to support wall-like props. Three-foot beams form right triangles with 10-foot beams to allow them to stand, as shown in the image.

What is x, the angle at which the diagonal beam meets the 10-foot beam at the top of the frame?

16.7°, 17.5°, 72.5°,73.3°"

The value of angle x would be 16.7 degrees.

<h3>What is the right triangle?</h3>

A right-angle triangle is a triangle that has a side opposite to the right angle the largest side and is referred to as the hypotenuse.

The angle of a right angle is always 90 degrees.

In order to find the value of x, a tan would be used.

This is because we have given the opposite and adjacent sides as 10 ft and 3 ft.

Tan Ф = opposite / adjacent

Tan Ф =  (3/10)

= 16.7 degrees

The value of angle x would be 16.7 degrees.

Learn more about a right angle;

brainly.com/question/7116550

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6 0
1 year ago
Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
melamori03 [73]

Answer:

6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs AB=3, BC=4, and AC=5. The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base b and height h is given by A=\frac{1}{2}bh. Therefore, the area of this right triangle is:

A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}

The other triangle is a bit trickier. Triangle \triangle ADC is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by:

A=\sqrt{s(s-a)(s-b)(s-c)}, where a, b, and c are three sides of the triangle and s is the semi-perimeter (s=\frac{a+b+c}{2}).

The semi-perimeter, s, is:

s=\frac{5+5+4}{2}=\frac{14}{2}=7

Therefore, the area of the isosceles triangle is:

A=\sqrt{7(7-5)(7-5)(7-4)},\\A=\sqrt{7\cdot 2\cdot 2\cdot 3},\\A=\sqrt{84}, \\A=2\sqrt{21}\:\mathrm{cm^2}

Thus, the area of the quadrilateral is:

6\:\mathrm{cm^2}+2\sqrt{21}\:\mathrm{cm^2}=\boxed{6+2\sqrt{21}\:\mathrm{cm^2}}

4 0
3 years ago
What is the solution for x in the equation
devlian [24]

Answer:

C. x=5/2

Step-by-step explanation:

-2x+10x=34-14

(8x=20 ) /:8

x=5/2

3 0
2 years ago
8 is what percent of 2500
Nataly [62]
8 percent of 2500 is 200.
5 0
3 years ago
Read 2 more answers
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