All categories

3 years ago

Y=6x+5 find the slope

Mathematics

2 answers:

tatiyna3 years ago

8 0

Answer:

slope- 6

Step-by-step explanation:

y=mx+b

y= outcome of the equation being done to x

m=slope

b=starting point on the you axis

x=the plug in on the x axis

y=6x+5. example: x=1

y=6 (1)+5

y=11

slope=6

Zina [86]3 years ago

3 0

Answer:

find the slope? the slope is the number attached to the x so itd be 6

You might be interested in

CAN SOMEONE HELP ME WITH THIS PROBLEM URGENT 5 STAR RATING AND BRAINLY IF SOLVED!

faust18 [17]

The answer that I got is $17.60

7 0

3 years ago

What is the slope of a line that is perpendicular to the line y = 8x + 5?−8 -1/8 1/8 8

Cerrena [4.2K]

Answer:

-1/8

Step-by-step explanation:

When slopes are perpendicular that means it's completely opposite.

The opposite of 8 is 1/8

But 8 is positive that means we have to make the pereldicular slope negative

Therefore your answer is -1/8

Hope this helps p,z mark brainliest!

6 0

3 years ago

Read 2 more answers

You are playing a board game and your playing piece

SCORPION-xisa [38]

2 green spaces, 2 star spaces, 2 question mark spaces

3 0

3 years ago

Marine biologists have determined that when a shark detectsthe presence of blood in the water, it will swim in the directionin w

siniylev [52]

Solution :

a). The level curves of the function :

$C(x,y) = e^{-(x^2+2y^2)/10^4}$

are actually the curves

$e^{-(x^2+2y^2)/10^4}=k$

where k is a positive constant.

The equation is equivalent to

$x^2+2y^2=K$

$\Rightarrow \frac{x^2}{(\sqrt K)^2}+\frac{y^2}{(\sqrt {K/2})^2}=1, \text{ where}\ K = -10^4 \ln k$

which is a family of ellipses.

We sketch the level curves for K =1,2,3 and 4.

If the shark always swim in the direction of maximum increase of blood concentration, its direction at any point would coincide with the gradient vector.

Then we know the shark's path is perpendicular to the level curves it intersects.

b). We have :

$\triangledown C= \frac{\partial C}{\partial x}i+\frac{\partial C}{\partial y}j$

$\Rightarrow \triangledown C =-\frac{2}{10^4}e^{-(x^2+2y^2)/10^4}(xi+2yj),$ and

$\triangledown C$ points in the direction of most rapid increase in concentration, which means $\triangledown C$ is tangent to the most rapid increase curve.