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aleksandr82 [10.1K]
3 years ago
5

How to write the fraction 6/10 as a decimal number

Mathematics
1 answer:
Inga [223]3 years ago
6 0
To write that as a decimal would be 0.60
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Write -0.06 as a fraction
torisob [31]

-\frac{6}{100}

Sorry if wrong

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3 years ago
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The greatest common factor of 30.48.60
Elena-2011 [213]
30= 3*10
30= 3*2*5

48= 12*4
48= 3*4*4
48= 3*2*2*2*2

60= 3*20
60= 3*10*2
60= 3*2*5*2

The GCF is 3*2 because all 3 numbers contain a 3 and a 2 in their prime factorizations.

Final answer: 6
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The radius, diameter, or circumference of a circle is given. Find the missing measures. Round to the nearest hundredth if necess
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Answer:

B

r=9.7

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Step-by-step explanation:

Given diameter of 19.4

r = d/2

19.4/2

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2(pi)(9.7)

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3 years ago
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Find the average value of the function on the given interval.<br> f(x)=2 ln x; [1,e]
JulijaS [17]

Answer:

f_{avg}=\frac{1}{e-1}

Step-by-step explanation:

We are given that a function

f(x)=2lnx

We have to find the average value of function on the given interval [1,e]

Average value of function on interval [a,b] is given by

\frac{1}{b-a}\int_{a}^{b}f(x)dx

Using the formula

f_{avg}=\frac{1}{e-1}\int_{1}^{e}lnx dx

By Parts integration formula

\int(uv)dx=u\int vdx-\int(\frac{du}{dx}\int vdx)dx

u=ln x and v=dx

Apply by parts integration

f_{avg}=\frac{1}{e-1}([xlnx]^{e}_{1}-\int_{1}^{e}(\frac{1}{x}\times xdx))

f_{avg}=\frac{1}{e-1}(elne-ln1-[x]^{e}_{1})

f_{avg}=\frac{1}{e-1}(e-0-e+1)=\frac{1}{e-1}

By using property lne=1,ln 1=0

f_{avg}=\frac{1}{e-1}

8 0
3 years ago
1/4 and 1/2 common denominators​
Paha777 [63]

Answer:

4

Step-by-step explanation:

5 0
3 years ago
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