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sammy [17]
2 years ago
13

I could use some help on this one! Thanks!

Mathematics
2 answers:
FrozenT [24]2 years ago
4 0

Answer:

A.) 458  R2

4 5 8

9 | 4 1 2 4

3 6  

5 2

4 5

7 4

7 2

2

458 with a remainder of 2

Lemur [1.5K]2 years ago
3 0
458
the answer is the last one
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Rearrange the formula a = v^2/ r for v
BabaBlast [244]
Isolate the v.

a = v^2/2

First multiply 2 to both sides

a(2) = v^2/2(2)

2a = v^2

Isolate the v, root both sides

√2a = √v^2
✓2a = v

✓2a = v should be your answer


Hope this helps
7 0
3 years ago
Find the sum of these polynomials.
Genrish500 [490]

Answer:

C

Step-by-step explanation:

add the two x^2 parts    =  10 x^2

 so answer is B or C

  add the constants   7 + 6 = 13     so answer C

7 0
1 year ago
Read 2 more answers
Given the equation -5x+2y=-10 what is the equation of the line perpendicular to the line?
meriva

Answer:

The equation of the perpendicular line would be y = -2/5x - 1

Step-by-step explanation:

In order to find this line, we must first find the slope of the original line. We do this by solving for y.

-5x + 2y = -10

2y = 5x - 10

y = 5/2x - 5

This shows us a slope of 5/2. TO find the perpendicular slope, we use the opposite and reciprocal. This means we negative 5/2 to get -5/2 and then we flip it to get -2/5. Now that we have this, we can use the slope and the point in point-slope form to get the equation.

y - y1 = m(x - x1)

y - 1 = -2/5(x + 5)

y - 1 = -2/5x - 2

y = -2/5x - 1

4 0
3 years ago
The value of
marusya05 [52]

\large\underline{\sf{Solution-}}

We have to find out the value of the fraction.

<u>Let us assume that:</u>

\sf \longmapsto x =2 +   \dfrac{1}{2 +  \dfrac{1}{2 +  \dfrac{1}{2 + ... \infty} } }

<u>We can also write it as:</u>

\sf \longmapsto x =2 + \dfrac{1}{x}

\sf \longmapsto x =\dfrac{2x + 1}{x}

\sf \longmapsto  {x}^{2}  =2x + 1

\sf \longmapsto {x}^{2}  - 2x - 1 = 0

<u>Comparing </u>the given <u>equation</u> with <u>ax² + bx + c = 0,</u> we get:

\sf \longmapsto\begin{cases} \sf a =1 \\ \sf b =  - 2 \\ \sf c =  - 1 \end{cases}

<u>By quadratic formula:</u>

\sf \longmapsto x =  \dfrac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}

\sf \longmapsto x =  \dfrac{2 \pm \sqrt{ {( - 2)}^{2} - 4(1)( - 1)} }{2 \times 1}

\sf \longmapsto x =  \dfrac{2 \pm \sqrt{4 + 4} }{2 \times 1}

\sf \longmapsto x =  \dfrac{2 \pm \sqrt{8} }{2}

\sf \longmapsto x =  \dfrac{2 \pm2 \sqrt{2} }{2}

\sf \longmapsto x = 1 \pm\sqrt{2}

\sf \longmapsto x = \begin{cases} \sf 1  + \sqrt{2} \\ \sf 1 -  \sqrt{2}  \end{cases}

<u>But </u><u>"</u><u>x"</u><u> cannot be negative. Therefore:</u>

\sf :\implies x = 1 + \sqrt{2}

So, the value of the fraction is 1 + √2.

4 0
2 years ago
The value of a collectible is changing such that dv/dt = 2t/(sqrt(t^2+1)) given in 4/year, and t is the number of years from 200
alina1380 [7]

Answer:

Diviértete tratando de conseguirlo porque no sé, así que sí, pero no

Step-by-step explanation:

5 0
3 years ago
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