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Bingel [31]
3 years ago
13

Help me solve this question please for 10 points

Mathematics
1 answer:
ankoles [38]3 years ago
3 0

Answer: D for the first one and B for the second

Step-by-step explanation:

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Hello, I need help finding the solutions of the equation log base 2 (x+8)+2=2 log base 2 (x)
yuradex [85]
\bf log_{{  a}}\left(  \frac{x}{y}\right)\implies log_{{  a}}(x)-log_{{  a}}(y)
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% Logarithm of exponentials
log_{{  a}}\left( x^{{  b}} \right)\implies {{  b}}\cdot  log_{{  a}}(x)
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{{  a}}^{log_{{  a}}x}=x\impliedby \textit{log cancellation rule}\\\\
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\bf log_2(x+8)+2=2log_2(x)\implies log_2(x+8)-2log_2(x)=-2
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log_2\left(\cfrac{x+8}{x^2}  \right)=-2\implies 2^{log_2\left(\cfrac{}{}\frac{x+8}{x^2}  \right)}=2^{-2}\implies \cfrac{x+8}{x^2}=\cfrac{1}{2^2}
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4x+32=x^2\implies 0=x^2-4x-32
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0=(x+4)(x-8)\implies 
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0=x+4\implies &-4=x\\
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6 0
3 years ago
Read 2 more answers
Multiple the binomials (x+3)^2
maxonik [38]

Answer:

=x^2+6x+9

Step-by-step explanation:

\left(x+3\right)^2\\\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a+b\right)^2=a^2+2ab+b^2\\a=x,\:\:b=3\\=x^2+2x\cdot \:3+3^2\\\mathrm{Simplify}\:x^2+2x\cdot \:3+3^2:\quad x^2+6x+9\\x^2+2x\cdot \:3+3^2\\\mathrm{Multiply\:the\:num\\bers:}\:2\cdot \:3=6\\=x^2+6x+3^2\\3^2=9\\=x^2+6x+9

8 0
3 years ago
A box has three balls, one white and two red. We select one ball, put it back in the box, and select a second ball (sampling wit
Dennis_Churaev [7]

Answer:

See explaation

Step-by-step explanation:

Given

Represent the balls with the first letters

W =1

R =2

Solving (a): P(F) --- White balls twice

The event of F is:

F = \{(W,W)\}

So:

P(F) = P(W) * P(W)

P(F) = \frac{n(W)}{n} * \frac{n(W)}{n}

P(F) = \frac{1}{3} * \frac{1}{3}

P(F) = \frac{1}{9}

Solving (b): P(G) --- two different colors

The event of G is:

G = \{(W,R),(R,W)\}

So:

P(G) = P(W) * P(R) + P(R) * P(W)

P(G) = \frac{n(W)}{n} * \frac{n(R)}{n} + \frac{n(R)}{n} * \frac{n(W)}{n}

P(G) = \frac{1}{3} * \frac{2}{3} + \frac{2}{3} * \frac{1}{3}

P(G) = \frac{2}{9} + \frac{2}{9}

P(G) = \frac{4}{9}

Solving (c): P(H) --- White picked first

The event of H is:

H = \{(W,R),(W,W)\}

So:

P(H) = P(W) * P(R) + P(W) * P(W)

P(H) = \frac{n(W)}{n} * \frac{n(R)}{n} + \frac{n(W)}{n} * \frac{n(W)}{n}

P(H) = \frac{1}{3} * \frac{2}{3} + \frac{1}{3} * \frac{1}{3}

P(H) = \frac{2}{9} + \frac{1}{9}

P(H) = \frac{3}{9}

P(H) = \frac{1}{3}

Solving (d): F and G, mutually exclusive?

We have:

F = \{(W,W)\}

G = \{(W,R),(R,W)\}

Check for common elements

n(F\ n\ G) = 0

<em>Hence, F and G are mutually exclusive</em>

Solving (e): G and G, mutually exclusive?

We have:

G = \{(W,R),(R,W)\}

H = \{(W,R),(W,W)\}

Check for common elements

n(G\ n\ H) = 1

<em>Hence, F and G are not mutually exclusive</em>

7 0
3 years ago
6 is what percent of 8%
kupik [55]

Answer:

75

Step-by-step explanation:

8% of x =6

8x/100=6

x=600/8=75

8 0
3 years ago
Read 2 more answers
3x + x + x + x − 3 − 2 = 7 + x + x In the equation above, what is the value of x?
algol13

Answer:

x=3

Step-by-step explanation:

3x + x + x + x − 3 − 2 = 7 + x + x

Combine like terms

6x -5 = 7+2x

Subtract 2x from each side

6x-2x -5 = 7+2x-2x

4x-5 =7

Add 5 to each side

4x-5+5 = 7+5

4x =12

Divide by 4

4x/4 = 12/4

x = 3

7 0
3 years ago
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