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son4ous [18]
3 years ago
6

I need a 4 letter code Please help fast!

Mathematics
1 answer:
anzhelika [568]3 years ago
5 0
The correct answer is POMS
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P (2, 3) and Q (6, 10) are two points on the Cartesian plane.
lara31 [8.8K]

Step-by-step explanation:

Given:

(x_1, \: y_1 ) =(2, \:3)\:\:\&\:\: (x_2, \: y_2) =(6, \:10)

l(PQ) =  \sqrt{ {(x_1 - x_2)}^{2} +  {(y_1 - y_2)}^{2}}  \\  \\  = \sqrt{ {(2 - 6)}^{2} +  {(3 - 10)}^{2}} \\  \\  = \sqrt{ {( - 4)}^{2} +  {( - 7)}^{2}}  \\  \\  =  \sqrt{16 + 49}  \\  \\  =  \sqrt{65}  \\  \\ \therefore \purple{ \boxed{  l(PQ) = 8.06 \: units}}\\\\

Let S be the mid-point of PQ.

\therefore S = \{\frac{x_1+x_2}{2}, \:\:\frac{y_1+y_2}{2}\} \\\\= \{\frac{2 +6}{2}, \:\:\frac{3+10}{2}\} \\\\= \{\frac{8}{2}, \:\:\frac{13}{2}\} \\\\\therefore S= \{4, \:\:6.5\} \\\\

Equation of line PQ is given as:

\frac{y-y_1}{y_1 - y_2}=\frac{x-x_1}{x_1 - x_2} \\\\\therefore  \frac{y-3}{3 - 10}=\frac{x-2}{2 - 6} \\\\\therefore  \frac{y-3}{-7}=\frac{x-2}{-4} \\\\\therefore  \frac{y-3}{7}=\frac{x-2}{4} \\\\\therefore 4(y-3)=7(x-2)\\\\\therefore 4y-12=7x-14\\\\\therefore 7x-14 - 4y + 12=0\\\\\red{\boxed {\therefore 7x-4y - 2 =0}}

4 0
3 years ago
Read 2 more answers
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