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WARRIOR [948]
3 years ago
8

Mr. Romeo wants to make a solution of NaOH. He measures out 97.68 grams and puts it into 3 liters

Chemistry
1 answer:
Studentka2010 [4]3 years ago
8 0

Answer:  Molarity of the solution is 0.813 M.

Explanation:

Given : Mass of NaOH = 97.68 g

Volume of solution = 3 L

The molar mass of NaOH is 39.99 g/mol. Hence, moles of NaOH are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{97.68 g}{39.99 g/mol}\\= 2.44 mol

Molarity is the number of moles of solute present in a liter of solution. Therefore, molarity of given solution is calculated as follows.

Molarity = \frac{no. of moles of solute}{Volume (in L)}\\= \frac{2.44 mol}{3 L}\\= 0.813 M

Thus, we can conclude that molarity of the solution is 0.813 M.

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What is the amount of solute required if the solution is 50 ml and the solvent is 35 ml. Solve and explain
e-lub [12.9K]

Answer:

15 mL of the solute

Explanation:

From the question given above, the following data were obtained:

Solution = 50 mL

Solvent = 35 mL

Solute =?

Solution is simply defined as:

Solution = solute + solvent

With the above formula, we can easily obtain the solute in the solution as follow:

Solution = 50 mL

Solvent = 35 mL

Solute =?

Solution = solute + solvent.

50 = solute + 35

Collect like terms

50 – 35 = solute

15 = solute

Solute = 15 mL

Therefore, 15 mL of the solute is required.

3 0
3 years ago
What is the concentration (in ppm) of Mn7+ in a 0.00300 M KMnO4 solution?  Note:  for dilute aqueous solutions, 1 ppm = 1 mg/L.
aleksklad [387]

We know that there is 1 mole of Mn for every 1 mole of KMnO4, therefore the molarity of Mn is similar with KMnO4:

Mn = 0.00300 M

Molar mass of Mn is 54.94 g / mol. Molarity (M) is moles / L, therefore:

Mn = (0.00300 moles / L) * (54.94 g / mol) * (1000 mg / g)

<span>Mn = 164.82 mg / L = 164.82 ppm</span>

3 0
3 years ago
*<br> The prevailing weather patterns of a region
elena-s [515]

Answer:

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Explanation:

8 0
3 years ago
How much water should be mixed with 237 ml of​ ammonia, whose strength is​ 100%, in order to create a mixture that is diluted to
azamat

<u>Answer</u>

79 ml


<u>Explanation</u>

You have 237 237 ml of​ ammonia, whose strength is​ 100%.

If you want to make it 75%, then;

let 75%  ⇒ 237 ml of ammonia and

   25% ⇒  x ml of water.

∴ x = (25% ×237) / 75%

       = 5,925/75

         = 79 ml of water.


8 0
4 years ago
Read 2 more answers
What is the molality of a solution that contains 418.8 g HCl in 4.62 kg water?
hram777 [196]

Answer:

a. 2.49

Explanation:

Molar mass of HCl= 36.46 g

So, no. of moles=418.8/36.46=11.48

Molality= no. of moles/mass of solvent= 11.48/4.62= 2.49

5 0
3 years ago
Read 2 more answers
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