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3 years ago

An experiment requires that enough C3H8O be used to yield of oxygen .

1 answer:

8 0

Answer: So if you had 570 cm of ribbon, then 570%2F8.5=67.05 which means that about 67 students can do the experiment (round down to the nearest whole number).

Explanation: If you had 8.5 cm of ribbon, then only 8.5%2F8.5=1 student can do the experiment. If you had 17 cm of ribbon, then 17%2F8.5=2 students can do the experiment.

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A. Gallium is produced by the electrolysis of a solution obtained by dissolving gallium oxide in concentrated NaOH(aq). Calculat

liraira [26]

Answer:

A)Mass of gallium plated out is 0.3440 grams

B) For 0.67 hours current of 5.79 A must to be applied to plate out 8.70 g of tin.

Explanation:

To calculate the total charge, we use the equation:

$C=I\times t$

where,

C = Charge

I = Current in time t (seconds)

To calculate the moles of electrons, we use the equation:

$\text{Moles of electrons}=\frac{C}{F}$

where,

F = Faraday's constant = 96500

A) The equation for the deposition of Ga(s) from Ga(III) solution follows:

$Ga^{3+}(aq.)+3e^-\rightarrow Ga(s)$

I = 0.790 A, t = 30.0 min = 1800 seconds

$C=I\times t$

$C=0.790 A\times 1800 s=1422 C$

Moles of electron transferred:

$=\frac{1422 C}{96500 F}=0.01474 mol$

Now, to calculate the moles of gallium, we use the equation:

$\text{Moles of Gallium}=\frac{\text{Moles of electrons}}{n}$

n = number of electrons transferred = 3

$\text{Moles of Gallium}=\frac{0.01474 mol}{3}=0.004913 mol$

Mass of 0.004913 moles of gallium = 0.004913 mol × 70 g/mol=0.3440 g

B) The equation for the deposition of Sn(s) from Sn(II) solution follows:

$Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)$

Moles of tin = $\frac{8.70 g}{119 g/mol}=0.07311 mol$

n = number of electrons transferred = 2

$\text{Moles of tin}=\frac{\text{Moles of electrons}}{n}$

Moles of electron = $n\times \text{Moles of tin}$

$=2\times 0.07311 mol=0.14622 mol$

Charge transferred during time t :

$\text{Moles of electrons}=\frac{C}{F}$

$C=96500 F\times 0.14622 mol=14,110.23 C$

Current applied for t time = I = 5.79 A

$t=\frac{C}{I}=\frac{14,110.23 C}{5.79 A}=2,437 s=0.67 hrs$

For 0.67 hours current of 5.79 A must to be applied to plate out 8.70 g of tin.

5 0

4 years ago

What are the two parts of a solution?

Vlad [161]

The 2 parts or components that make up a solution would be the solute and the solvent.

6 0

3 years ago

Who developed the gas law that relates pressure and temperature?

Bad White [126]

Explanation:

physicist Robert Boyle

5 0

3 years ago

how could you check that when the calcium carbonate is reacting with hydrochloric acid the gas given off is carbon dioxide

pav-90 [236]

Answer:

CaCO3 + 2 HCl => CaCl2 + CO2 + H2O

Explanation:

CO2 will burst out when the reaction occurs in water, and the ions will be dissociated: Ca(2+) + 2 Cl (-)

7 0

3 years ago

Calculate the wavelength of a photon of light with a frequency of 6.17 x 1014 Hz.

PtichkaEL [24]

Answer:

4.86 × 10^-7m

Explanation:

Wavelength = C/f

C (Speed) of light = 3 × 10^8

f = 6.17 × 10^14

Wavelength = (3 × 10^8)/ (6.17 × 10^14)

= 4.86 × 10^-7m

7 0

3 years ago