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PSYCHO15rus [73]
3 years ago
15

For the following, identify the most likely value for x.a. BHx b. CHx c. NHx d. CH2Clx

Chemistry
1 answer:
vekshin13 years ago
5 0

Given :

a. BH_x b. CH_x c. NH_x d. CH_2Cl_x .

To Find :

Find the most likely vale of x for each one .

Solution :

a . BH_x

Because boron have valency of 3 .

So , x = 3 .

b . CH_x

Valency of carbon is 4 .

x = 4 .

c . NH_x

Valency of nitrogen is 3 .

Therefore , x = 3 .

d . CH_2Cl_x

Now ,we know valency of carbon is 4 and hydrogen is 1 .

Also , two hydrogen are already there .

So , only 2 electrons left to share .

Since , chlorine have valency of 1 .

Therefore , only 2 electrons of chlorine can connect .

x = 2 .

Hence , this is the required solution .

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