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PSYCHO15rus [73]
3 years ago
15

For the following, identify the most likely value for x.a. BHx b. CHx c. NHx d. CH2Clx

Chemistry
1 answer:
vekshin13 years ago
5 0

Given :

a. BH_x b. CH_x c. NH_x d. CH_2Cl_x .

To Find :

Find the most likely vale of x for each one .

Solution :

a . BH_x

Because boron have valency of 3 .

So , x = 3 .

b . CH_x

Valency of carbon is 4 .

x = 4 .

c . NH_x

Valency of nitrogen is 3 .

Therefore , x = 3 .

d . CH_2Cl_x

Now ,we know valency of carbon is 4 and hydrogen is 1 .

Also , two hydrogen are already there .

So , only 2 electrons left to share .

Since , chlorine have valency of 1 .

Therefore , only 2 electrons of chlorine can connect .

x = 2 .

Hence , this is the required solution .

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For the equilibrium PCl5(g) PCl3(g) + Cl2(g), Kc = 2.0 × 101 at 240°C. If pure PCl5 is placed in a 1.00-L container and allowed
Cloud [144]

Answer:

the equilibrium concentration of [PCl₅] is 3.64*10⁻³ M

Explanation:

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Kc= [PCl₃]*[Cl₂]/[PCl₅] = 2.0*10¹ M = 20 M

and [A] denote concentrations of A

if initially the mixture is pure PCl₅ , then it will dissociate according to the reaction and since always one mole of PCl₃(g) is generated with one mole of Cl₂(g) , the total number of moles of both at the end is the same → they have the same concentration → [PCl₃(g)] = [Cl₂]=0.27 M

therefore

Kc= [PCl₃]*[Cl₂]/[PCl₅] = 0.27 M* 0.27 M /[PCl₅] = 20 M

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