5 valence electrons
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Answer:
last choice
Explanation:
Specific heat of a metal is j/kg-c
It says nothing about melting point or heat of fusion
A = twice B = 2 * j/kg-c B = j/kg-c
if j is constant and mass is the same we can write this more like
A = 2 /C and B = 1/C
or A ~ C/2 and B~ C
now you can see that the temp change in A will be 1/2 that of B
1)
4 molecules of Hygdrogen is produced.
2)
4 atoma of Oxygen is produced.
3)
1 molecule of Fe3O4 is formed.
4)
1mole of 3 Fe : mole of 4 H2O
3 :4
=3/4
5) There are 2×4 = 8atoms of hydrogen on Reactant side.
Answer:
0.75 L
Explanation:
V1/T1 = V2/T2
V1 = 0.520 L
T1 = 18 C = 291 K (make sure to convert to Kelvin by adding 273 to the Celsius temperature)
V2 = ?
T2 = 422 K
Solve the equation for V2
V2 = V1T2/T1
V2 = (0.520 L)(422 K) / (291 K) = 0.754 L ≈ 0.75 L (since it says to only give two significant figures)
